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boyakko [2]
3 years ago
8

HELP PLEASE I NEED HELP

Mathematics
1 answer:
Vesna [10]3 years ago
4 0

C. \: 8 \sqrt{3}✅

Step-by-step explanation:

\sqrt{192}  \\  =  \sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 3}  \\  =   \sqrt{ {2}^{2} \times  {2}^{2} \times  {2}^{2}    \times 3}  \\ =  \sqrt{ {8}^{2} \times 3 }    \\ =  8\sqrt{3}

\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘

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3 years ago
The sum of two consecutive odd numbers is 284. Find each number please.
Vlad [161]
We can solve this by finding one of the numbers first
Let the smaller number be y. 
Since these 2 numbers are consecutive odd numbers, the larger number should be 2 more than the smaller one (y+2).

Therefore, 
y + (y+2) = 284
2y +2 = 284
shift +2 to the other side and turn it into -2
2y = 284 - 2
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shift x2 to the other side and turn it into /2
y = 282/2
y = 141

Now we got the smaller number, which is 141, we can also find the larger number by adding 2 to it. 141+2 = 143, 
Therefore, your answer is 141 and 143

8 0
3 years ago
Read 2 more answers
How to solve this one​
ivolga24 [154]

The x,y = -6, -5. Hope this helped, and have a great day! :D

6 0
3 years ago
What is the value of p so that the expession 6x+3-(8x-5) is equivalent to (px+8)?​
kiruha [24]

Answer:

-2

Step-by-step explanation:

The first equation simplifies to -2x+8 so p should be replaced with -2

4 0
3 years ago
For the function P(x) = x3 − 9x, at the point (2, −10), find the following. (a) the slope of the tangent to the curve (b) the in
Shalnov [3]

Answer:

3, in both a), b)

Step-by-step explanation:

a) The slope of the line tangent to the curve that passes through the point (2,-10) is equal to the derivative of p at x=2.

Using differentiation rules (power rule and sum rule), the derivative of p(x) for any x is p'(x)=3x^2-9. In particular, the value we are looking for is p'(2)=3(2^2)-9=12-9=3.

If you would like to compute the equation of the tangent line, we can use the point-slope equation to get y=3(x-2)-10=3x-16

b) The instantaneus rate of change is also equal to the derivative of P at the point x=2, that is, P'(2). This is equal to p'(2)=3.

4 0
3 years ago
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