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boyakko [2]
3 years ago
8

HELP PLEASE I NEED HELP

Mathematics
1 answer:
Vesna [10]3 years ago
4 0

C. \: 8 \sqrt{3}✅

Step-by-step explanation:

\sqrt{192}  \\  =  \sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 3}  \\  =   \sqrt{ {2}^{2} \times  {2}^{2} \times  {2}^{2}    \times 3}  \\ =  \sqrt{ {8}^{2} \times 3 }    \\ =  8\sqrt{3}

\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘

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Which expression is equivalent to (2^5)^-2
irinina [24]

<u><em>1/1024 is the correct answer.</em></u> First you had to apply exponent rule, and it gave us, \frac{1}{(2^5)^2}, or 2^5^*^2. Then you can also refine, and it gave us, 2^10, or \frac{1}{2^10}. And it gave us the answer is 2^1^0=2*2*2*2*2*2*2*2*2*2=1024, or 1/1024 is the correct answer. Hope this helps! And thank you for posting your question at here on brainly, and have a great day. -Charlie

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=log%20xy%5E%7B2%7D" id="TexFormula1" title="log xy^{2}" alt="log xy^{2}" align="absmiddle" cla
swat32

Answer:

sry I can't understand how to do this question

5 0
3 years ago
Can someone help me with this I'll give a crown thing please hurry!​
gulaghasi [49]

Answer:

1) 1: 107

  2: 73

  3: 107

  4: 73

  5: 107

  6: 73

  7: 107

  8: 73

3) 1: 128

  2: 52

  3: 128

  4: 52

  5: 128

  6: 52

  7: 128

  8: 52

Step-by-step explanation:

  • Vertical, corresponding, alternate exterior, and alternate interior angles are all congruent (equal).
  • Angles such as same side exterior and same-side interior are supplementary; meaning these angles add up to 180°.
6 0
3 years ago
The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2).
zavuch27 [327]

Answer:

(–1, 1)

(4, –2)

Step-by-step explanation:

Let

(x,y) ----> the coordinates of point C

Applying the Pythagoras Theorem

(-1-4)^2+(-2-1)^2=(x-4)^2+(y-1)^2+(x+1)^2+(y+2)^2

step 1

Find the possibles values of x

(-1-4)^2=(x-4)^2+(x+1)^2\\\\25=x^{2}-8x+16+x^{2}+2x+1\\\\2x^{2}-6x-8=0

Simplify

x^{2}-3x-4=0

Solve the quadratic equation

x^{2}-3x-4=(x+1)(x-4)

The values of x are

x=-1 and x=4

step 2

Find the possibles values of y

(-2-1)^2=((y-1)^2+(y+2)^2\\\\9=y^{2}-2y+1+y^{2}+4y+4\\\\2y^{2}+2y-4=0

Simplify

y^{2}+y-2=0

Solve the quadratic equation

y^{2}+y-2=(y+2)(y-1)

The values of y are

y=-2, y=1

therefore

The possibles coordinates of point C are

(-1,1),(4,-2)

3 0
3 years ago
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