Answer:
Step-by-step explanation:
38 quarts
Answer:
The probability a random selected radish bunch weighs between 5 and 6.5 ounces is 0.8185
Step-by-step explanation:
The weight of the radish bunches is normally distributed with a mean of 6 ounces and a standard deviation of 0.5 ounces
Mean = 
Standard deviation = 
We are supposed to find the probability a random selected radish bunch weighs between 5 and 6.5 ounces i.e.P(5<x<6.5)

At x = 5

Z=-2

At x = 6.5

Z=1
Refer the z table for p value
P(5<x<6.5)=P(x<6.5)-P(x<5)=P(Z<1)-P(Z<-2)=0.8413-0.0228=0.8185
Hence the probability a random selected radish bunch weighs between 5 and 6.5 ounces is 0.8185
Answer:
The lower bound is,
and the upper bound is
.
Step-by-step explanation:
Let the random variable <em>X</em> follows a normal distribution with mean <em>μ </em>and standard deviation <em>σ</em>.
The the random variable <em>Z, </em>defined as
is standardized random variable also known as a standard normal random variable. The random variable
.
The standard normal random variable has a symmetric distribution.
It is provided that
.
Determine the upper and lower bound as follows:
![P(-z\leq Z\leq z)=0.51\\P(Z\leq z)-P(Z\leq -z)=0.51\\P(Z\leq z)-[1-P(Z\leq z)]=0.51\\2P(Z\leq z)-1=0.51\\2P(Z\leq z)=1.51\\P(Z\leq z)=0.755](https://tex.z-dn.net/?f=P%28-z%5Cleq%20Z%5Cleq%20z%29%3D0.51%5C%5CP%28Z%5Cleq%20z%29-P%28Z%5Cleq%20-z%29%3D0.51%5C%5CP%28Z%5Cleq%20z%29-%5B1-P%28Z%5Cleq%20z%29%5D%3D0.51%5C%5C2P%28Z%5Cleq%20z%29-1%3D0.51%5C%5C2P%28Z%5Cleq%20z%29%3D1.51%5C%5CP%28Z%5Cleq%20z%29%3D0.755)
Use a standard normal table to determine the value of <em>z.</em>
The value of <em>z</em> such that P (Z ≤ z) = 0.755 is 0.69.
The lower bound is,
and the upper bound is
.
0.08 can be written as 8%
Answer:
$2662.5 is the answer in my opinion