Answer:
proof
Step-by-step explanation:
Statements
Reasons
<2 is congruent to <5; Segment AB is congruent to Segment DE
Given
<3≅<4
Vertical angle theorem
ΔCDB≅ΔCAE
AAS
Segment BC is congruent to Segment EC
CPCTC
Answer:
l think that the answer is (-3,2). pliz can you mark me the brainest.
Using pythagorean's theorem
a^2+b^2=c^2
a being 3
b being 4
we'll get
9+16=25
where 5 is the hypotenuse and also c.
c^2 = 5^2
Isolate the x. Subtract 4x from both sides, and add 2 to both sides
2x (-4x) - 2 (+2) > 4x (-4x) + 6 (+2)
2x - 4x > 6 + 2
Simplify. Combine like terms
-2x > 8
Isolate the x. Divide -2 from both sides. Note that you are <em>dividing a negative number</em>. When doing so, flip the sign.
-2x/-2 > 8/-2
x > 8/-2
x < -4
x < -4, or (1) is your answer
hope this helps
586/10 -> 293/5 -> 58 3/5