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Katena32 [7]
3 years ago
13

A bridge on a river is modeled by the equation h = -0.2d^2 + 2.25d, where h is the height and d is the horizontal distance. For

cleaning and maintenance purposes a worker wants to tie a taut rope on two ends of the bridge so that he can slide on the rope. The rope is at an angle defined by the equation -d + 6h = 21.77. If the rope is attached to the bridge at points A and B, such that point B is at a higher level than point A, at what distance from the ground level is point A?
Mathematics
1 answer:
Gelneren [198K]3 years ago
7 0
We are given the equations
h = -0.2d² + 2.25d
-d + 6h = 21.77

Solving for d in the second equation:
-d + 6h = 21.77
d = 6h - 21.77
Substituting to the first equation:
h = -0.2(6h - 21.77)² + 2.25(6h - 21.77)
The value of h can then be solved with is
h = 3.9968
so
d = 2.2108
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Let's subtract 9z from the left-hand side. That way, the 5w will be alone on the left-hand side.

And remember, anything we do on one side we do to the other side.

</span><span>5w + 9z - 9z = 2z + 3w - 9z
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The 3w term on the right-hand side needs to be removed. So, subtract each side by 3w.

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Now, we need to divide each side by 2 to see what the w variable is equal to.

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we know that

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