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2 years ago

22. What is the area of minor sector DFE?

Mathematics

1 answer:

Shalnov [3]2 years ago

3 0

The area of the minor sector DFE is gotten as; D: 66.1 square cm

<h3>How to find area of sector?</h3>

Formula for area of sector is;

A = (θ/360) * πr²

We are given;

minor angle; θ = 100°

radius; r = 8.7 cm

Thus;

A = (100/360) * π(8.7²)

A = 66.1 square cm

Read more about Area of Sector at; brainly.com/question/22972014

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Examine this system of equations. Which numbers can be multiplied by each equation so that when the two equations are added toge

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In the elimination method one variable is eliminated from the system of equation to find the value of other.

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<h3>What is elimination method?</h3>

To solve the system of equation and find the value of the variables, the elimination method is used.

In this method one variable is eliminated from the system of equation to find the value of other.

Given information-

The system of equation given in the problem is,

$\dfrac{1}{4}x -\dfrac{1}{6}y =5\\$ ......1

Let the above equation as equation 1.

The second equation given in the problem is,

$\dfrac{4}{5}x +\dfrac{3}{8}y =10$ ......2

Let the above equation as equation 2.

To eliminate the y term, make the coefficient of <em>y</em> of both the equation equal.

As the coefficient of <em>y</em> of the equation 2 is 3/8. Thus multiply second equation with 8 to eliminate coefficient. Thus,

$8\times \dfrac{4}{5}x +8\times\dfrac{3}{8}y =8\times10\\$

$\dfrac{32}{5}x +3y =80$ .....3

Multiply equation 1 with 18 to make the coefficient of y equal. Thus,

$18 \times\dfrac{1}{4}x -18\times\dfrac{1}{6} \times y =18 \times5$

$\dfrac{18}{4}x -3 =90$ ......4

Add equation 3 and equation 4 as,

$\dfrac{32}{5}x +3y+ \dfrac{18}{4}x -3y =80+90$

$\dfrac{32}{5}x + \dfrac{18}{4}x =170$

Hence the first equation must be multiplied by 18 and second equation must be multiplied by 8.

Learn more about the elimination method here;

brainly.com/question/7013345

4 0

3 years ago

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