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3 years ago

How to graph quadratic equations

1 answer:

6 0

If you are graphing quadratic equations of the type
ax^2 + bx + c = 0

The equation will look like a "U" <span>if "a" is positive </span>or it will look like an upside-down "U" <span>if "a" is negative </span>

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Help meeeee;)........

mylen [45]

Step-by-step explanation:

ABC be the given isosceles right triangle such that <B = 90° , side AC is the hypotenuse; and, AB= BC

Then, (AB)^2 + (BC)^2 = (AC)^2…. Pythagoras theorem.

(AC)^2 = 98 sq. cm. ( given)

So, (AB)^2 + ((BC)^2 = 98

But, AB = BC = a ( say) …. ( given)

Therefore, a^2 + a^2 = 98

Or, 2a^2 = 98.

So, a^2 = 98 / 2 = 49

Hence, a = AB = BC = √49 = 7 cm.

The side AC ( the hypotenuse) = √98 = √(7 *7*2)

= 7 *√2 = 7* 1.414 = 9..898cm., say, 9.9 cm.

Hence, the three sides of the right isosceles triangle are 7 cm, 7cm and ~ 9.9 cm. Answer

<h2>please mark me as brainlist please </h2>

7 0

2 years ago

Read 2 more answers

andrew-mc [135]

Answer:

The angle of depression from Platform A to Platform B is $43.1^{\circ}$

Step-by-step explanation:

Refer the attached figure

The horizontal distance between the platforms is 500 feet i.e. BC = 500

The length of the zip-line is 685 feet i.e. AB = 685

We are supposed to find the angle of depression from Platform A to Platform B

Hypotenuse = 685

Base = 500

$Cos \theta = \frac{Base}{Hypotenuse}\\Cos \theta = \frac{500}{685}\\\theta = cos^{-1}(\frac{500}{685})\\\theta = 43.11^{\circ}$

Hence the angle of depression from Platform A to Platform B is $43.1^{\circ}$

4 0

3 years ago

Help plzzzzzzzzzzzzzzzzzzzzz

prohojiy [21]

Answer:

c = ${\boxed{\boldsymbol{29}}}$ km

Step-by-step explanation:

Here's the required formula to find the missing side of triangle by pythagoras theorem :

${\longrightarrow{\pmb{\sf{{(a)}^{2} + {(b)}^{2} = {(c)}^{2}}}}}$

$\purple\star$ a = 20 km
$\purple\star$ b = 21 km
$\purple\star$ c = ?

Substituting all the given values in the formula to find the third side of triangle :

$\begin{gathered} \quad{\longrightarrow{\sf{{(a)}^{2} + {(b)}^{2} = {(c)}^{2}}}} \\ \\ \quad{\longrightarrow{\sf{{(20)}^{2} + {(21)}^{2} = {(c)}^{2}}}} \\ \\ \quad{\longrightarrow{\sf{(20 \times 20) + (21 \times 21) = {(c)}^{2}}}} \\ \\ \quad{\longrightarrow{\sf{(400) + (441) = {(c)}^{2}}}} \\ \\ \quad{\longrightarrow{\sf{400 + 441 = {(c)}^{2}}}} \\ \\ \quad{\longrightarrow{\sf{841= {(c)}^{2}}}} \\ \\ \quad{\longrightarrow{\sf{c = \sqrt{841}}}} \\ \\ \quad{\longrightarrow{\sf{\underline{\underline{\purple{c = 29 \: km}}}}}}\end{gathered}$

Hence, the length of missing side of triangle is 29 km.

$\rule{300}{2.5}$

3 0

2 years ago

What's two thirds of a straight line?

Komok [63]

Well if the straight line is equal to 1 then your answer is 2/3 but if the straight line is not equal to 1 you need to know what it is equal to or you could use the equation y = (2/3)x
"x" would be the length of the straight line and "y" would be two-thirds of it

6 0

3 years ago

A like has two-fold Symmetry

Vikki [24]

Answer:

yes

Step-by-step explanation:

5 0

2 years ago