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2 years ago

Place 3 numbers between 12 and 60 to make a sequence of 5 numbers with a common difference

Mathematics

1 answer:

Vilka [71]2 years ago

5 0

The 3 numbers which should be placed between 12 and 60 are; 24, 36 and 48.

<h3>What three numbers should be placed between 12 and 60?</h3>

It follows from the task content that the first and last numbers are; 12 and 60 respectively.

Hence, since the difference between 12 and 60 is 48 and there are 4 transitions between the two numbers to have 5 total numbers,

It follows that the common difference is; 48/4 = 12 and the three numbers required are; 24,36 and 48.

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$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}$

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A road is perpendicular to a highway leading to a farmhouse d miles away.

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Let x be the distance of automobile from the point of intersection and distance between the automobile and farmhouse is 'h' miles.

Then by Pythagoras theorem,

h² = d² + x²

By taking derivative on both the sides of the equation,

$(2h)\frac{dh}{dt}=(2x)\frac{dx}{dt}$

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