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salantis [7]
3 years ago
15

40 points to whoever can answer for me!

Mathematics
2 answers:
luda_lava [24]3 years ago
8 0

Answer:

x≤-3      2 ≤x<7  

Step-by-step explanation:

(x^2+x-6) /(x-7) ≤0

Factor the numerator

(x+3)(x-2) / (x-7)≤0

Critical points are

X =-3  X =2  X=7

We need to check the values when

x≤3  -3 ≤ x≤2           2 ≤x<7   x>7  

(x cannot be 7 because then the denominator is zero)

and see when it is less than 0

Substitute a value in and see if factor is positive or negative

x≤-3

(negative)(negative) / (negative) =   negative

-3 ≤x≤2    

(positive)(negative) / (negative) = positive  this range does not work

      2 ≤x<7  

(positive)(positive) / (negative) = negative

x>7

(positive)(positive) / (positive)

stepan [7]3 years ago
7 0

Answer:

The second option is the correct answer.

Thank you.

I've answered as fast as I can to answer your question.Hope you understood it.

Pls mark my answer as brainliest and follow me.

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3 years ago
I WILL GIVE A FREAKING BRAINLIEST!!!!!!!!!!!
UkoKoshka [18]

Answer:

  0.5 < t < 2

Step-by-step explanation:

The function reaches its maximum height at ...

  t = -b/(2a) = -16/(2(-16)) = 1/2 . . . . . . where a=-16, b=16, c=32 are the coefficients of f(t)

The function can be factored to find the zeros.

  f(t) = -16(t^2 -1 -2) = -16(t -2)(t +1)

The factors are zero for ...

  x = -1 and x = +2

The ball is falling from its maximum height during the period (0.5, 2), so that is a reasonable domain if you're only interested in the period when the ball is falling.

5 0
3 years ago
What is the value of b in this equation?<br> b- 2 = 18
mariarad [96]
The answer is 20 because 20 - 2 will give you 18
5 0
3 years ago
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This graph represents a quadratic function. What is the function’s equation written in factored form and in vertex form?
creativ13 [48]

Answer:

Part a) The function’s equation written in vertex form is

f(x)=2(x-2)^2-8

Part b) The function’s equation written in factored form is equal to

f(x)=2x(x-4)

Step-by-step explanation:

Part a) What is the function’s equation written in vertex form?

we know that

The equation of a vertical parabola written in vertex form is equal to

f(x)=a(x-h)^2+k

where

a is a coefficient

(h,k) is the vertex

Looking at the graph

The vertex is the point (2,-8)

substitute

f(x)=a(x-2)^2-8

Find the value of the coefficient a

take one point from the graph

(0,0)

substitute in the equation

0=a(0-2)^2-8\\0=4a-8\\4a=8\\a=2

therefore

The function’s equation written in vertex form is

f(x)=2(x-2)^2-8

Part b) What is the function’s equation written in factored form?

we know that

The equation of a vertical parabola written in factored form is equal to

f(x)=a(x-x_1)(x-x_2)

where

a is a coefficient

x_1 and x_2 are the zeros or x-intercepts of the function

Remember that the x-intercept is the value of x when the value of the function is equal to zero

Looking at the graph

The zeros or x-intercepts of the function are

x=0 and x=4

so

f(x)=a(x-0)(x-4)

f(x)=ax(x-4)

Find the value of the coefficient a

take one point from the graph

(2,-8)

substitute

-8=a(2)(2-4)\\-8=-4a\\a=2

therefore

The function’s equation written in factored form is equal to

f(x)=2x(x-4)

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Answer:

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Step-dream ):)

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