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1 year ago

Find the measure of the angles indicated

Mathematics

1 answer:

GalinKa [24]1 year ago

8 0

Both angles have a measure of 125°.

<h3>How to find the measure of the angles?</h3>

Assuming the two horizontal lines are parallel, we know that the measure of the two indicated angles must be the same one.

Then:

-1 + 14x = 12x + 17

Now we need to solve this for x:

14x - 12x = 17 + 1

2x = 18

x =18/2 = 9

Now that we know the value of x we can replace it in any of the expressions for the angles:

-1 + 14*9 = 125°

Both angles have a measure of 125°.

If you want to learn more about angles:

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Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE

Viktor [21]

Answer:

Step-by-step explanation:

Given the function f(x) = 8x³ − 12x² − 48x, <em>the critical point of the function occurs at its turning point i,e at f'(x) = 0</em>

First we have to differentiate the function as shown;

$f'(x)= 3(8)x^{3-1}- 2(12)x^{2-1} - 48x^{1-1}\\ \\f'(x) = 24x^2 - 24x-48x^0\\\\f'(x) = 24x^2 - 24x-48\\\\At \ the\turning\ point\ f'(x)= 0\\24x^2 - 24x-48 = 0\\\\\\$

$Dividing \ through \ by \ 24\\\\x^2-x-2 = 0\\\\On \ factorizing\\\\x^2-2x+x-2 = 0\\\\x(x-2)+1(x-2) = 0\\\\(x-2)(x+1) = 0\\\\x-2 = 0 \ and \ x+1 = 0\\\\x = 2 \ and \ -1$

Hence the critical numbers of the function are (2, -1)

8 0

3 years ago

The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6

viktelen [127]

Answer:

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

The proportion of contracts involved between five and 10 inclusive bidders is 0.5.

The proportion of contracts involved strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders No. contracts Relative frequency of contracts

2 6 6/102=0.0588

3 20 20/102=0.1961

4 24 24/102=0.2353

5 18 18/102=0.1765

6 13 13/102=0.1275

7 7 7/102=0.0686

8 5 5/102=0.049

9 6 6/102=0.0588

10 2 2/102=0.0196

11 1 1/102=0.0098

Total 102

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

We have to find proportion of contracts involved between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The proportion of contracts involved between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10= Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The proportion of contracts involved strictly between five and 10 bidders is 0.304.

8 0

3 years ago

Eight more then seventimes a number (x) is atleast twenty nine

Mademuasel [1]

Answer:A number increased by seventeen is equal to seventy-three. x + 17 = 73

Some number decreased by seven is thirty-three. x - 7 = 33

A number increased by twelve is forty. x + 12 = 40

A number increased by fifteen is sixty-two. x + 15 = 62

Eight less than a number is nine. x - 8 = 9

A number divided by 11 is 4. x/11 = 4

Seven more than three times a number is 19. 3x + 7 = 19

Four more than five times a number is thirty-six. 5x + 4 = 35

Eight less than nine times a number is eleven. 9x - 8 = 11

Twelve more than four times a number is seven. 4x + 12 = 7

Seven more than triple a number is fifteen. 3x + 7 = 15

Seven times a number increased by eight equals twenty-three. 7x + 8 = 23

Eight more than six times a numbers is eleven. 6x + 8 = 11

Nine times a number increased by thirteen is twelve. 9x + 13 = 12

The quotient of a number and four is seventeen. x/4 = 17

A number increased by seven is twenty-five. x + 7 = 25

Fifty-five is the sum of a number and sixteen. x + 16 = 55

The product of a number and eleven is seventy-five. 11x = 75

Eight times a number increased by eleven is thirty-seven. 8x + 11 = 37

The difference of a number and twelve is thirty-four. x - 12 = 34

Step-by-step explanation:

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No because when you cross multiply 9/24 has a bigger number

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3 years ago

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Eddi Din [679]

Depends on what kind of a triangle

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