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quester [9]
3 years ago
8

PLEASE HELP ME!!!

Mathematics
2 answers:
Helen [10]3 years ago
8 0

Answer:

Just took it!

Step-by-step explanation:

Ede4ka [16]3 years ago
7 0

The roots of the quadratic equation ax^2+bx+c=0 are

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}.

Here the given quadratic equation is 5x^2-13x+7=0. Here a=5,b=-13,c=7.

The roots are

x=\frac{13 \pm \sqrt{13^2-4*5*7}}{2*5} \\ x=\frac{13 \pm \sqrt{29}}{10}

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Can someone help me find x
nadya68 [22]

Answer:


Step-by-step explanation:

2 equal 90° angles, we can use an equation

x + 15 = 90

x = 90 - 75

x = 15°

-------------------------

check

90 = 15 + 75

90 = 90

the answer is good



7 0
4 years ago
The quadratic function h(t)=-16.1t^2+150 models a balls height in feet over time in seconds after it is dropped from a 15 story
Allushta [10]

someone please answer

3 0
4 years ago
Please help me with the question
aliina [53]

Answer:

first you correct the no

in mixed fraction

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7 0
2 years ago
An arrow is shot vertically upward from a platform 16ft high at a rate of 190ft/sec. When will the arrow hit the ground? Use the
Contact [7]
H(t) = -16t2 + 186t + 43

at the ground h = 0

hence; -16t2 + 186t + 43 = 0

solving this quadratic equation using the quadratic formula ; a = -16, b = 186, c = 43 ; x = (-b +-(b2 - 4ac)1/2)/2a

gives t = 11.8 seconds to the nearest tenth (note that the negative root has no practical significance)
5 0
3 years ago
Read 2 more answers
(06.04)
LenKa [72]
0,2 because that is where the lines meet.
4 0
3 years ago
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