Question

Ppppp-pp help please.

Answer 1

Answer:

There are two complex roots:

• $-3\pm i$

============

Given equation:

• x² - 6x + 10 = 0

The standard form is:

• ax² + bx + c = 0

Compared we can find values of the coefficients and the constant:

• a = 1, b = - 6, c = 10

Substitute these values into quadratic formula:

     $x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}$

and work out roots:

    $x=\dfrac{-(-6)\pm\sqrt{(-6)^2-4*1*10} }{2*1}=x=\dfrac{6\pm\sqrt{36-40} }{2}=\dfrac{6\pm2\sqrt{-1} }{2}=3 \pm i$