Answer:
14 and 6
Step-by-step explanation:
Let's start by naming the first number x.
We can name the second number y.
We can set up equations to model our situation.
x+y=2x-8
x-y=2y-4
Let's simplify the equations.
x+y=2x-8
Subtract 2x from both sides
-x+y=-8
__________
x-y=2y-4
Subtract 2y from both sides.
x-3y=-4
Add the two equations together to eliminate x.
x-3y=-4
-x+y=-8
________
0x-2y=-12
-2y=-12
Divide both sides by -2.
y=6
The second number is 6.
Plug that back in.
x+6=2x-8
Subtract x from both sides
6=x-8
Add 8 to both sides
x=14
The first number is 14
Answer:
C. There are infinitely many solutions.
Step-by-step explanation:
3x – 6 < 3x + 13
Subtract 3x from each side
-6 < -13
This inequality is always true.
There are infinitely many solutions.
Step 1: Find f'(x):
f'(x) = -6x^2 + 6x
Step 2: Evaluate f'(2) to find the slope of the tangent line at x=2:
f'(2) = -6(2)^2 + 6(2) = -24 + 12 = -12
Step 3: Find f(2), so you have a point on y=f(x):
f(2) = -2·(2)^3 + 3·(2)^2 = -16 + 12 = -4
So, you have the point (2,-4) and the slope of -12.
Step 4: Find the equation of your tangent line:
Using point-slope form you'd have: y + 4 = -12 (x - 2)
That is the equation of the tangent line.
If your teacher is picky and wants slope-intercept, solve that for y to get:
y = -12 x + 20
Answer:
Step-by-step explanation:
3/4
25 > 2x + 8 - 66
first simplify all numbers
25 > 2x + (8 - 66)
25 > 2x - 58
Then add 58 to both sides
25 (+58) > 2x - 58 (+58)
83 > 2x
Finally divide 2 from both sides to isolate the x
83/2 > 2x/2
41.5 > x
hope this helps
