The answer would be A.
Explanation:
If they enter with one car, that’s a price of $3 for the car alone. Because there’s also a fee for each person who enters, and there is a family of 5 who enters, x is representative of the cost for each person who enters. Therefore, there would be 5 x’s and one 3 that when solved would add up to the total of $45 they spent. That would mean A is correct because the equation would be x + x + x + x + x + 3 = 45.
Answer:
Like terms are terms whose variables are the same.
We can only add them because if they does not have the same variable you do not actually know if the variables are equivalent and you will get the wrong answer.
Step-by-step explanation:
Ex: 4z,7z,108z,45z
Ex: 4w-2h+7a-2w
You can not add 4w and 7a because you do not know what the variables equal so you do not know the true number so add or subtract by.
Answer:
I think It's option (B) 45
Step-by-step explanation:
But I am not sure It's correct or not
I hope It's helpful
9514 1404 393
Answer:
- 13 ft
- (a) 1 second; (b) t = 0, t = 1/2
Step-by-step explanation:
<h3>1. </h3>
Let w represent the length of the wire. Then the height of attachment is (w-1). The Pythagorean theorem tells us a relevant relation is ...
5² +(w -1)² = w²
w² -2w +26 = w² . . . . . . . eliminate parentheses, collect terms
26 = 2w . . . . . . . . . . . . add 2w
13 = w . . . . . . . . . . . . divide by 2
The length of the wire is 13 feet.
__
<h3>2. </h3>
(a) When h = 0, the equation is ...
0 = -16t^2 +8t +8
Dividing by -8 puts this into standard form:
2t^2 -t -1 = 0
Factoring, we get ...
(2t +1)(t -1) = 0
The positive value of t that makes a factor zero is t = 1.
It will take 1 second for the gymnast to reach the ground.
__
(b) When h = 8, the equation is ...
8 = -16t^2 +8t +8
Subtract 8 and divide by 8 to get ...
0 = -2t^2 +t
0 = t(1 -2t) . . . . factor out t
Values of t that make the factors zero are ...
t = 0
t = 1/2
The gymnast will be 8 feet above the ground at the start of the dismount, and 1/2 second later.
<h2>
Hello!</h2>
The answers are:
A.
and 
D.
and 
<h2>
Why?</h2>
To find which of the following pairs of numbers contains like fractions, we must remember that like fractions are the fractions that share the same denominator.
We are given two fractions that are like fractions. Those fractions are:
Option A.
and 
We have that:

So, we have that the pairs of numbers
and

Share the same denominator, which is equal to 6, so, the pairs of numbers contains like fractions.
Option D.
and 
We have that:

So, we have that the pair of numbers
and

Share the same denominator, which is equal to 7, so, the pairs of numbers constains like fractions.
Also, we have that the other given options are not like fractions since both pairs of numbers do not share the same denominator.
The other options are:

and

We can see that both pairs of numbers do not share the same denominator so, they do not contain like fractions.
Hence, the answers are:
A.
and 
D.
and 
Have a nice day!