Answer:
And solving for z we have
![P(Z](https://tex.z-dn.net/?f=P%28Z%3Cz%29%3D%200.4750%2B0.5%3D%200.9750)
And we can find the value for z with the following excel code:
"=NORM.INV(0.975,0,1)"
And we got z =1.96
![P(Z>z)= 0.1314](https://tex.z-dn.net/?f=%20P%28Z%3Ez%29%3D%200.1314)
And we can use the complement rule and we got:
![P(Z>z) = 1-P(Z](https://tex.z-dn.net/?f=%20P%28Z%3Ez%29%20%3D%201-P%28Z%3Cz%29%20%3D%200.1314)
![P(Z](https://tex.z-dn.net/?f=%20P%28Z%3Cz%29%3D%201-0.1314%3D%200.8686)
And we can find the value for z with the following excel code:
"=NORM.INV(0.8686,0,1)"
And we got z =1.120
![P(Z](https://tex.z-dn.net/?f=%20P%28Z%3Cz%29%3D%200.67)
And we can find the value for z with the following excel code:
"=NORM.INV(0.67,0,1)"
And we got z =0.440
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
We want this probability:
And solving for z we have
![P(Z](https://tex.z-dn.net/?f=P%28Z%3Cz%29%3D%200.4750%2B0.5%3D%200.9750)
And we can find the value for z with the following excel code:
"=NORM.INV(0.975,0,1)"
And we got z =1.96
For the next part we want to calculate:
![P(Z>z)= 0.1314](https://tex.z-dn.net/?f=%20P%28Z%3Ez%29%3D%200.1314)
And we can use the complement rule and we got:
![P(Z>z) = 1-P(Z](https://tex.z-dn.net/?f=%20P%28Z%3Ez%29%20%3D%201-P%28Z%3Cz%29%20%3D%200.1314)
![P(Z](https://tex.z-dn.net/?f=%20P%28Z%3Cz%29%3D%201-0.1314%3D%200.8686)
And we can find the value for z with the following excel code:
"=NORM.INV(0.8686,0,1)"
And we got z =1.120
For the next part we want to calculate:
![P(Z](https://tex.z-dn.net/?f=%20P%28Z%3Cz%29%3D%200.67)
And we can find the value for z with the following excel code:
"=NORM.INV(0.67,0,1)"
And we got z =0.440