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3 years ago

Vertical, Complementary and Linear Pair Angles

Mathematics

1 answer:

dlinn [17]3 years ago

4 0

1) Vertical angles-the angles will equal each other.
8+7x=9x-4
12+7x=9x
12=2x
x=6
2) Supplementary-Angles will add up to 180
6+13x+7x+14=180
20+20x=180
20x=160
x=8

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What is 21x^6y^5 divided by 14x^y^9 will make brainliest lot of points on the line too

Fiesta28 [93]

Answer:

$\dfrac{3x^4}{2y^4}$

Step-by-step explanation:

$\dfrac{21x^6y^5}{14x^2y^9}= \\\\\\\dfrac{21}{14}\cdot \dfrac{x^6}{x^2} \cdot \dfrac{y^5}{y^9}= \\\\\\\dfrac{3x^4}{2y^4}$

Hope this helps!

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3 years ago

Anybody know the correct answer?

earnstyle [38]

Since $\csc^2{x}=\frac{1}{\sin^2{x}}$ and $\cot^2{x}=\frac{\cos^2{x}}{\sin^2{x}}$ , we can rewrite the right side of the equation as

$\frac{1}{\sin^2{x}}-\frac{\cos^2{x}}{\sin^2{x}} =\frac{1-\cos^2{x}}{\sin^2{x}}$

Using the identity $\sin^2{x}+\cos^2{x}=1$ , we can subtract $\cos^2{x}$ from either side to obtain the identity $\sin^2{x}=1-\cos^2{x}$

substituting that into our previous expression, the right side of our equation simply becomes

$\frac{\sin^2{x}}{\sin^2{x}}=1$

We can now write our whole equation as

$3\tan^2{x}-2=1$

Adding 2 to both sides:

$3\tan^2{x}=3$

dividing both sides by 3:

$\tan^2{x}=1$

$\tan{x}=\pm1$

When 0 ≤ x ≤ π, tan x can only be equal to 1 when sin x = cos x, which happens at x = π/4, and it can only be equal to -1 when -sin x = cos x, which happens at x = 3π/4

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3 years ago

Which expression is equivalent to 4 • 4 • 4 • 4 • 4 • 4 • 4 • 4? A. 4 • 8 B. 84 C. 8 • 8 D. 48

Eduardwww [97]

Answer:

Step-by-step explanation:

We have 4 being multiplied by itself 8 times. this is written as

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4 years ago

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valkas [14]

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3 years ago

Trigonometric Identities and Applications?

alex41 [277]

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$\bf 8cos^2(\theta )-3cos(\theta )=0\implies \stackrel{common~factor}{cos(\theta )}[8cos(\theta )-3]=0\\\\
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cos(\theta )=0\implies \measuredangle \theta =cos^{-1}(0)\implies \measuredangle \theta =90^o\\\\
-------------------------------\\\\
8cos(\theta )-3=0\implies 8cos(\theta )=3\implies cos(\theta )=\cfrac{3}{8}
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\measuredangle \theta =cos^{-1}\left( \cfrac{3}{8}\right)$

22)

$\bf \begin{cases}
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3 years ago