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Eddi Din [679]
2 years ago
15

While performing a physical examination on Denny French, Dr. Giles uses what to examine Denny's eyes

SAT
1 answer:
valkas [14]2 years ago
8 0

While performing a physical examination on Denny French, Dr. Giles used an ophthalmoscope to examine Denny's eyes.

<h3>What is a disease?</h3>

A disease refers to any harmful and abnormal deviation of the body or body parts such as the eyes of a living organism from its normal structure or functional state due to the actions of pathogens, and it's typically accompanied by certain signs and symptoms.

<h3>What is an ophthalmoscope?</h3>

An ophthalmoscope can be defined as a type of instrument that is designed and developed to be used by an ophthalmologist to physically examine the interior of a patient's eye.

In this context, we can infer and logically deduce that while performing a physical examination on Denny French, Dr. Giles used an ophthalmoscope to examine Denny's eyes.

Read more on ophthalmoscope here: brainly.com/question/25800311

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the relationship between group size and percent woodland appears to be negative and nonlinear. which of the following statements
Aloiza [94]

The statement that explains such a relationship is that as the percent of woodland increases, the number of deer observed in a group decreases quickly at first and then more slowly

  • Nonlinear relationship is a type of relationship that changes that takes place in the output change not in direct proportion to alterations (changes) in any of the inputs.
  • This type of relationship does not produce any straight line but produces a curve line.
  • Negative relationship  is simply known as negative or inverse correlation that occurs between two variables. That is when that one variable increases, the other decreases, and vice-versa. As in the case of the woodland and the beer. When woodland increases, the deer decreases and vice versa

Conclusively, we can say that as the statement that explains such a relationship is that as the percent of woodland increases, the number of deer observed in a group decreases quickly at first and then more slowly

Learn more from:

brainly.com/question/18101129

3 0
2 years ago
A possible disadvantage to watching this scene, as opposed to reading it silently, is that viewers are required to conceptualize
Eduardwww [97]
I don’t know the answer but I’m going figure it out
6 0
2 years ago
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Which would best help an athlete be successful in strategy training?
aev [14]

These listed below would best help an athlete be successful in strategy training. Attitude is main strategy which can determine how much you can achieve.

Time of training should be for approx. 45-60 minutes to improve fitness.

To overcome the failures and to achieve goals, it is essential to have a person compelling vision. A lot of athletes achieve success after failures due to their vision. They have a dream which motivates them to perform better.

<h3></h3><h3>Which person is known as athlete?</h3>

A person who is expert in sports and other forms of physical exercise.

Athlete should  set goals which is considered to be the first step in the process of achieving success.  Goals keep successful athletes motivated in the ground while playing.

For more details regarding, athlete training, visit:

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8 0
2 years ago
Once you have your heap structure created, next you must use it as a backing structure to a priority queue. Develop a PriorityQu
saveliy_v [14]

Using the knowledge in computational language in python it is possible to write a code that Develop a PriorityQueue data structure in a file.

<h3>Writting the code in python:</h3>

<em>import sys</em>

<em>class Node:</em>

<em>def __init__(self,key):</em>

<em>self.left = None</em>

<em>self.right = None</em>

<em>self.val = key</em>

<em>self.parent = None</em>

<em>class MinHeap:</em>

<em>def __init__(self, maxsize):</em>

<em>self.maxsize = maxsize</em>

<em>self.size = 0</em>

<em>self.Heap = Node(-1 * sys.maxsize )</em>

<em>self.FRONT = self.Heap</em>

<em># A utility function to do inorder tree traversal</em>

<em>def isLeaf(self, node):</em>

<em>if node.left == None and node.right == Node:</em>

<em>return True</em>

<em>return False</em>

<em># Function to swap two nodes of the heap</em>

<em>def swap(self, node1, node2):</em>

<em>node1.data, node2.data = node2.data, node1.data</em>

<em># Function to heapify the node at pos</em>

<em>def minHeapify(self, node):</em>

<em># If the node is a non-leaf node and greater</em>

<em># than any of its child</em>

<em>if not self.isLeaf(node):</em>

<em>if (node.data > node.left.data or</em>

<em>node.data > node.right.data):</em>

<em># Swap with the left child and heapify</em>

<em># the left child</em>

<em>if node.left.data < node.right.data:</em>

<em>self.swap(node, node.left)</em>

<em>self.minHeapify(node.left)</em>

<em># Swap with the right child and heapify</em>

<em># the right child</em>

<em>else:</em>

<em>self.swap(node, node.right)</em>

<em>self.minHeapify(node.right)</em>

<em># Function to insert a node into the heap</em>

<em>def insert(self, element):</em>

<em>if self.size >= self.maxsize :</em>

<em>return</em>

<em>self.size+= 1</em>

<em>self.bst_insert(FRONT, element)</em>

<em>current = FRONT</em>

<em>while current.parent != None and current.data < current.parent.data:</em>

<em>self.swap(current, current.parent)</em>

<em>current = current.parent</em>

<em># Function to print the contents of the heap</em>

<em>def Print(self):</em>

<em>self.inorder()</em>

<em># Function to build the min heap using</em>

<em># the minHeapify function</em>

<em>def inorder(self, root):</em>

<em>if root:</em>

<em>inorder(root.left)</em>

<em>print(root.val)</em>

<em>inorder(root.right)</em>

<em>def bst_insert(self, root, node):</em>

<em>if root is None:</em>

<em>root = node</em>

<em>else:</em>

<em>root.next = node</em>

<em>self.FRONT = node</em>

<em># Driver Code</em>

<em>if __name__ == "__main__":</em>

<em>r = Node(50)</em>

<em>bst_insert(r,Node(30))</em>

<em>bst_insert(r,Node(20))</em>

<em>bst_insert(r,Node(40))</em>

<em>bst_insert(r,Node(70))</em>

<em>bst_insert(r,Node(60))</em>

<em>bst_insert(r,Node(80))</em>

<em># Print inoder traversal of the BST</em>

<em>inorder(r)</em>

<em>print('The minHeap is ')</em>

<em>minHeap = MinHeap(15)</em>

<em>minHeap.insert(5)</em>

<em>minHeap.insert(3)</em>

<em>minHeap.insert(17)</em>

<em>minHeap.insert(10)</em>

<em>minHeap.insert(84)</em>

<em>minHeap.insert(19)</em>

<em>minHeap.insert(6)</em>

<em>minHeap.insert(22)</em>

<em>minHeap.insert(9)</em>

<em>minHeap.minHeap()</em>

<em>minHeap.Print()</em>

<em>print("The Min val is " + str(minHeap.remove()))</em>

See more about python at brainly.com/question/13437928

#SPJ1

6 0
1 year ago
How species in the salt marsh community use cord-grass?
MArishka [77]
The Marsh Crab uses cordgrass as a source of food.
The Periwinkle Snail eats the algae on the cordgrass and it uses it as a place to hide from predators.
The Seaside Sparrow users cordgrass to make nests
7 0
3 years ago
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