Inflection point is the point where the second derivative of a graph is zero.
y = (x+1)arctan xy' = (x+1)(arctan x)' + (1)arctan xy' = (x+1)/(x^2+1) + arctan xy'' = (x+1)(1/(1+x^2))' + 1/(1+x^2) + 1/(1+x^2)y'' = (x+1)(-1/(1+x^2)^2)(2x)+2/(1+x^2)y'' = ((x+1)(-2x)+1+x^2)/(1+x^2)^2y'' = (-2x^2-2x+2+2x^2)/(1+x^2)^2y'' = (-2x+2)/(1+x^2)^2
Solving for point of inflection: y'' = 00 = (-2x+2)/(1+x^2)^20 = -2x+2x = 1y(1) = (1+1)arctan(1) = 2 * pi/4 = pi/2
Therefore, E(1, pi/2).
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The smallest number of tiles Quintin will need in order to tile his floor is 20
The given parameters;
- number of different shapes of tiles available = 3
- area of each square shape tiles, A = 2000 cm²
- length of the floor, L = 10 m = 1000 cm
- width of the floor, W = 6 m = 600 cm
To find:
- the smallest number of tiles Quintin will need in order to tile his floor
Among the three different shapes available, total area of one is calculated as;

Area of the floor is calculated as;

The maximum number tiles needed (this will be possible if only one shape type is used)

When all the three different shape types are used we can get the smallest number of tiles needed.
The minimum or smallest number of tiles needed (this will be possible if all the 3 different shapes are used)

Thus, the smallest number of tiles Quintin will need in order to tile his floor is 20
Learn more here: brainly.com/question/13877427
1 is the value of a ther is always a imaginary 1 infront of a letter
The answer is y = 5+ 8x/7
Answer:
Remember, we did not necessarily round up or down, but to the hundred that is nearest to 32. When rounding to the nearest hundred, like we did with 32 above, we use the following rules: A) We round the number up to the nearest hundred if the last two digits in the number are 50 or above.
Step-by-step explanation: