Ask question

Ask question

All categories

3 years ago

9

Write a linear function that models each situation. a 24. The enrollment at a local community college was 5,000 in 1960. In the

year 2000, the enrollment was 15,000. Assuming that the enrollment grows linearly since 1960, write a linear equation that represents the enrollment of the college x years after 1960.

1 answer:

tia_tia [17]3 years ago

8 0

9514 1404 393

Answer:

y = 250x +5000

Step-by-step explanation:

The "initial" enrollment is 5000, when x=0 years after 1960.

The rate of change of enrollment is ...

change of enrollment / change in time

= (15000 -5000)/(2000 -1960)

= 10000/40 = 250 . . . . students per year

Then the desired equation is ...

y = 250x + 5000

You might be interested in

What are the limit laws???

Whitepunk [10]

In Calculus - limits, there are several limits law, but the most common ones should be the following:

limx-->a [f(x) + g(x)] = L+M
limx-->a [f(x) - g(x)] = L-M
limx-->a f(x)/g(x) = L/M, if M does not equal to 0

Hope this helps!

8 0

3 years ago

Estimate by first rounding each number to the nearest integer.

posledela

$4 \frac{1}{9} + 2\frac{ 2}{13} =4 \frac{13}{117} + 2\frac{ 18}{117} =6\frac{31}{117}\approx 6\\ \\Answer: \ \ C.\ \ 6$

5 0

3 years ago

Name 2 two-dimensional figures that are cross sections of both the cube and pyramid.

Mice21 [21]

Answer:

The cross section of this circular cylinder is a circle.

5 0

4 years ago

Rewrite in simplest terms. 8(-5d-9) -3(-6d+10)

Gnesinka [82]

Answer:

− 22 d − 102

Step-by-step explanation:

6 0

3 years ago

Mr. Javier purchased a number of pencils for ₱180 and sold all except 6 at a profit of ₱2 per pencil. With the total amount rece

Luba_88 [7]

Answer:

36 pencils

$Cost = 0.2$

Step-by-step explanation:

Given

Cost Price = 180

Represent the number of items by x

This implies that the cost of each item is $\frac{x}{180}$

$Selling\ Price = Cost + Profit$

$Selling\ Price = \frac{x}{180} + 2$

Since all but 6 items were sold, the total selling price is:

$Total = (x - 6)(\frac{x}{180} + 2)$

This amount can be used to buy 30 more items.

So, we have:

$(x - 6)(\frac{x}{180} + 2) = x + 30$

Multiply both sides by 180

$180 * (x - 6)(\frac{x}{180} + 2) =180(x + 30)$

$(x - 6)(x + 360) = 180x + 5400$

Expand brackets

$x\² + 360x - 6x - 2160 = 180x + 5400$

$x\² + 354x - 2160 = 180x + 5400$

Equate to 0

$x\² + 354x - 180x - 2160 - 5400 = 0$

$x\² + 174x - 7560 = 0$

Expand

$x\² + 210x - 36x - 7560 = 0$

$x(x + 210) - 36(x + 210) = 0$

$(x - 36)(x + 210) = 0$

$x - 36 = 0$ or $x + 210 = 0$

$x = 36$ or $x = -210$

<em>Since, number of items can't be negative, we have to discard x = -210.</em>

Hence:

$x = 36$

<em>We can then conclude that, Mr. Javier purchased 36 pencils</em>

Recall that

$Cost = \frac{x}{180}$

$Cost = \frac{36}{180}$

$Cost = 0.2$

5 0

4 years ago