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Stels [109]
3 years ago
10

Plz help me answer this it is solving combinations

Mathematics
1 answer:
olga2289 [7]3 years ago
7 0
I dont believe there are any

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Ms. Lane borrowed $1,000 from her bank for one year at an interest rate of 10 percent. During that year, the price level went up
Lunna [17]

Answer:

Consider the complete question is,

'Ms. Lane borrowed $1,000 from her bank for one year at an interest rate of 10 percent. During that year, the price level went up by 15 percent. Which of the following statements is correct?

a. Ms. Lane will repay the bank fewer dollars than she initially borrowed.

b. Ms. Lane's repayment will give the bank less purchasing power than it originally loaned her.

c. Ms. Lane's repayment will give the bank greater purchasing power than it originally loaned her.

d. Ms. Lane's repayment will give the bank the same purchasing power that it originally loaned her.'  

Solution :

We have,

The borrowed amount, P = $ 1,000,

Interest rate, r = 10% = 0.1,

Time, t = 1 year,

Thus, the returned amount,

A=P(1+r)^t=1000(1+0.1)^1=1000(1.1) = \$ 1100

∵ A > P

⇒ Ms. Lane will repay the bank greater dollars than she initially borrowed.

Now,  the price level went up by 15 percent,

∵ 1000 + 15% of 1000 = 1000 + 150 = 1500

And, 1500 > 1100

⇒ Ms. Lane's repayment will give the bank less purchasing power than it originally loaned her.

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Step-by-step explanation:

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A hypothetical square grows so that the length of it's diagonals are increasing at a rate of 8 m/min. How fast is the area of th
guapka [62]

Answer:

32m^{2}/min

Step-by-step explanation:

We let the length of the square be l, the diagonal be z and the area be A.

Then by Pythagoras theorem;

l^{2}+l^{2}=z^{2}\\2l^{2}=z^{2}

The are of a square of length l is given as;

A=l^{2}

Combining these two equations yields;

z^{2}=2A

A=\frac{z^{2} }{2}

Next, we have been given;

\frac{dz}{dt}=8

We are required to find;

\frac{dA}{dt} when z = 4

By chain rule;

\frac{dA}{dt}=\frac{dA}{dz}*\frac{dz}{dt}

Differentiating A=\frac{z^{2} }{2} with respect to z yields;

\frac{dA}{dz}=z

Therefore,

\frac{dA}{dt}=\frac{dA}{dz}*\frac{dz}{dt} = 8z

When z is 4m the area of the square will be increasing at a rate of;

8m/min * 4m = 32m^{2}/min

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