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erica [24]
2 years ago
5

Which table represents a linear function that has a slope of 5 and a y-intercept of 20?

Mathematics
2 answers:
erastovalidia [21]2 years ago
8 0

Answer:

The first image.

x |  y

-4 | 0

0 | 20  <--- When x = 0, the y value is the y-intercept.

4 | 40

8 | 60

Step-by-step explanation:

To check the slope, we can use the equation (y₂ - y₁) ÷ (x₂ - x₁) using any two pairs given. For this example, I'll use (-4, 0) and (4, 40).

                                                              x₂  y₂         x₁   y₁

(0 - 40) ÷ (-4 - 4)

(-40) ÷ (-8)

<u>Slope = 5</u>

<u></u>

~Hope this helps!~

JulsSmile [24]2 years ago
4 0

Answer:

<em><u>Table 1</u></em>

hope its correct:)

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245.76

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Solve 5r2 – 12 = 68. {±4} {±5} {±3} {±6}
sashaice [31]

Hey there!

Assuming you meant

5r^2 - 12 = 68

If so, follow these steps so it can be a little bit easier to solve

Firstly, we have to add by 12 on each of your sides

5r^2 -12 +12 \\ \\ 68 + 12

5r^2 = 5r^2 \\ \\ 68 + 12 = 80

We get: 5r^2 =80

Now, we have divide by 5 on each of your sides

\frac{5r^2}{5} = \frac{80}{5}

\frac{80}{5}  = 16

We get: r^2 = 16

r = ± \sqrt{16}

Therefore , your answer is:r = ±4

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

3 0
3 years ago
60 + 108 = 180<br> What property would this be
kvv77 [185]

Answer:

Non-intelligent

Step-by-step explanation:

It is wrong so who ever solved this equation is non-intelligent

5 0
2 years ago
a toy rocket is launched from the top of a 48 foot hill. The rockets initial upward velocity is 32 feet per second and its heigh
sdas [7]

Answer:

t = 2.11 seconds

Step-by-step explanation:

A toy rocket is launched from the top of a 48 foot hill. The rockets initial upward velocity is 32 feet per second and its height h at any given second t is modeled by the equation:

h=-16t^2+32t+48

Let us assume that we need to find the time by it to reach the ground. It means h = 0

-16t^2+32t+48=0

The above is a quadratic equation. The value of t is given by :

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So, it will take 2.11 seconds to reach the ground.

6 0
3 years ago
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