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Svetlanka [38]
3 years ago
7

Brian was thinking of a number. Brian adds 3 then divides by 2 to get an answer of 2.what was the original answer

Mathematics
1 answer:
Andreas93 [3]3 years ago
4 0

Reverse engineer

2*2-3=1

so its 1

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Pls help asap I will give brainerlist plus 25 points
kirza4 [7]

PEMDAS - Parenthesis, Exponents, Multiplication, Division, Addition, and Subtraction

First, we do the exponents.

5² - 4 · 6 + 11

= 25 - 4 · 6 + 11

Next, multiplication (according to PEMDAS).

= 25 - 24 + 11

Although PEMDAS says addition then do subtraction, please note that this is totally interchangeable. For the sake of this problem, subtraction will be done first.

= 25 - 24 + 11

= 1 + 11

Finally, addition.

= 12

This is your answer. Happy studying~

6 0
3 years ago
Read 2 more answers
Solve . 3/27 = w/54
WINSTONCH [101]

\frac{3}{27}=\frac{w}{54}    Multiply 54 to both sides to get "w" by itself

(54)\frac{3}{27}=\frac{w}{54}(54)

\frac{162}{27} =w

6 = w

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3 years ago
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Please help ASAP :{ jhjkhybblvklmmm
babunello [35]

Answer:

<h2>C</h2>

Step-by-step explanation:

V=0.5*b*l*h

V=0.5*10*28*12

V=10*14*12

V=10*168

V=1680 m^3 or C

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3 years ago
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Can someone solve this?
RoseWind [281]
I can the company sold 3,00 units in 2008, and 5,00 in 2012
3 0
3 years ago
One container is filled with a mixture that is 30%acid a second container is filled with a mixture that is 50%acid the second co
julsineya [31]

Answer:

The amount of acid in third container is =42%

Step-by-step explanation:

Given , one container is filled with a mixture that is 30% acid a second container filled with a mixture that is 50% acid and the second container 50% larger than the first .

Let, the volume of first container is = x

Then , the volume of second container = (x+ x of 50%)

                                                                 = x + 0.5 x

                                                                 = 1.5 x

Therefore the amount of acid in first container =x \times \frac{30}{100} = 0.3 x

The amount of acid in second container =1.5x \times \frac{50}{100}  = 0.75x

Total amount of acid= 0.3x + 0.75x = 1.05 x

Total amount  of solution = x+1.5x = 2.5x

The amount of acid in third container is = \frac{1.05x}{2.5x} \times 100% %

                                                                     = 42%

4 0
3 years ago
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