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leva [86]
1 year ago
6

HELPPPPPPPPPPPPPPPPPPP!

Mathematics
1 answer:
AlekseyPX1 year ago
7 0

Answer: Real, equal, rational.

Step-by-step explanation:

-x^2-8x-16=0\\-(x^2+8x+16)=0\\Multiply \ the\  left \ and\  right \ sides\  of\  the\  equation\  by \ -1:\\x^2+8x+16=0\\x^2+2*x*4+4^2=0\\(x+4)^2=0\\x+4=0\\x=-4.

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Assuming that the population is normally​ distributed, construct a 9090​% confidence interval for the population mean for each o
jasenka [17]

Given:

Set A: 1 4 4 4 5 5 5 8

Mean: 4.5

Standard dev: 1.9

 

Set B:

Mean: 4.5

Standard dev: 2.45

 

% =  90 

Set A:

Standard Error, SE = s/ √n =    1.9/√8 = 0.67  

Degrees of freedom = n - 1 =   8 -1 =  7   

t- score =  1.89457861

<span> <span><span> <span>   </span> </span> </span></span>

Width of the confidence interval = t * SE =     1.89457861* 0.67 = 1.272685913

Lower Limit of the confidence interval = x-bar - width =      4.5 - 1.272685913 = 3.23

Upper Limit of the confidence interval = x-bar + width =      4.5 + 1.272685913 = 5.77

The 90% confidence interval is [3.23, 5.77]

 

Set B:

Standard Error, SE = s/ √n =    2.45/√8 = 0.87  

Degrees of freedom = n - 1 =   8 -1 = 7   

t- Score =  1.89457861

<span> <span><span> <span>   </span> </span> </span></span>

Width of the confidence interval = t * SE =     1.89457861* 0.87 = 1.641094994

Lower Limit of the confidence interval = x-bar - width =      4.5 - 1.641094994 = 2.86

Upper Limit of the confidence interval = x-bar + width =      4.5 + 1.641094994 = 6.14

The 90% confidence interval is [2.86, 6.14]

 

<span>We can obviously see that sample B has more variation in the scores than sample A. The fact that the standard deviation is 2.45 for B and 1.9 for A). Therefore, they yield dissimilar confidence intervals even though they have the same mean and range.</span>

6 0
3 years ago
=
sergiy2304 [10]

Answer:

  Q, R

Step-by-step explanation:

All of the listed sets of numbers are Real numbers. The fraction is not an integer, so is not in sets I or N. Because it is a fraction, it is in set Q, and because R includes Q, ...

  the number is in sets Q and R

8 0
2 years ago
Given sample set A= {1,2,3,4,5} how many items are in the complement of set B if set B= all numbers greater than 2? OPTIONS : 3
Ostrovityanka [42]

Answer:

2

Step-by-step explanation:

It sounds like we are pretending A is the universe.  The only numbers in our world are 1,2,3,4, and 5.

You are given B is all numbers greater than 2.

The complement of B would all the elements not listed in B.

The elements in B are 3,4, and 5, since we are looking for numbers greater than 2 in our world of numbers above.

The elements not in B are 1 and 2.

So B complement is {1,2}.

There are 2 elements in our set for B complement. The elements that were counted were just the element 1 and the element 2.

6 0
3 years ago
2596 divided by 83 can't figure is out who ever does it gets $500 I really need help
worty [1.4K]

Answer:

2596\83 =31.2

Step-by-step explanation:

8 0
3 years ago
16y=14+9y please answer 23 points
NeTakaya

Answer:

<h2>y = 2</h2>

Step-by-step explanation:

16y=14+9y\qquad\text{subtract}\ 9y\ \text{from both sides}\\\\16y-9y=14+9y-9y\\\\7y=14\qquad\text{divide both sides by 7}\\\\\dfrac{7y}{7}=\dfrac{14}{7}\\\\y=2

4 0
3 years ago
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