Answer:
The price will be higher and output lower in absence of competition.
Explanation:
When the market does not have enough competition, it provides a certain degree of market power to the existing producers. They are able to regulate prices and output.
It is likely that the suppliers will provide a fewer quantities of goods at a higher price, in order to maximize their profits. The socially optimal level of output will not be produced in the market.
The resources will not be efficiently allocated and deadweight loss will exist.
Answer:
b. Jacob should be hired at the $20 per hour wage rate
<u>Options</u>
a. Sophia should do the drafting work herself because she has the lower opportunity cost
b. Jacob should be hired at the $20 per hour wage rate
c. Sophia should not hire Jacob because it would be faster for her to do the work herself
d. Jacob should be hired, but only if he is paid more than $30 per hour
Explanation:
Sophia cannot fullfil their client request on time without hiring an employee Assuming Jacob is the best possible candidate for Sophie she should consider to hire it as three hours of Jabor will cost 60 dollars while an hour of his work is worth 90 dollars
Thus, making convinient to hire it as there is a profit of 30 dollars.
We should also conider jacob will earn experience over time and this will make it a better employee in the long-run.
Answer:
Fifo
Explanation:
Because the stock that is bought first should be the one to be purchased first
Depreciating means to become less valuable over time, so I believe the correct answer is <span>b. become less valuable over time.</span>
Answer:
4.00
Explanation:
Given:
Upper Specification Limit, USL = 27
Lower Specification Limit, LSL = 21
Mean = 22
Standard deviation,
= 0.25
Required:
Find the process capability index
First center the mean by taking the average of the LSL and USL.



Use formula below to find process capability index:
![C_p_i = min [(\frac{USL - X}{3*\sigma}), (\frac{X - LSL}{3*\sigma})]](https://tex.z-dn.net/?f=%20C_p_i%20%3D%20min%20%5B%28%5Cfrac%7BUSL%20-%20X%7D%7B3%2A%5Csigma%7D%29%2C%20%28%5Cfrac%7BX%20-%20LSL%7D%7B3%2A%5Csigma%7D%29%5D%20)
![C_p_i = min [(\frac{27 - 24}{3*0.25}), (\frac{24 - 21}{3*0.25})]](https://tex.z-dn.net/?f=%20C_p_i%20%3D%20min%20%5B%28%5Cfrac%7B27%20-%2024%7D%7B3%2A0.25%7D%29%2C%20%28%5Cfrac%7B24%20-%2021%7D%7B3%2A0.25%7D%29%5D%20)
![= min [(\frac{3}{0.75}), (\frac{3}{0.75})]](https://tex.z-dn.net/?f=%20%3D%20min%20%5B%28%5Cfrac%7B3%7D%7B0.75%7D%29%2C%20%28%5Cfrac%7B3%7D%7B0.75%7D%29%5D%20)
![min [ (4.00), (4.00)]](https://tex.z-dn.net/?f=%20min%20%5B%20%284.00%29%2C%20%284.00%29%5D%20)
We are sullosed to take the minimum value, but since both values are equal, our process capability index will be 4.00
Therefore, the process capability index = 4.00