Question

The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = y minus 1 equals 1/4 left-parenthesis x minus 12 right-parenthesis.(x – 12). What is the standard form of the equation for this line?

Answer 1

The standard form is:

4y - x = -8

How to get the standard form of the line?

We know that the point-slope equation of the line is:

y - 1 = (1/4)*(x - 12)

Expanding the right side, we get:

y - 1 = (1/4)*x - 3

Now we can move the term with x to the left side:

y - (1/4)*x = +1 - 3

y - (1/4)*x = -2

Now we can multiply both sides by 4:

4y - x = -8

This is the standard form of the linear equation.

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Answer 2

The equation in point slope form is y-1 = 1/4(x - 12)

Equation of a line

The formula for calculating the equation of a line is expressed as;

y = mx + b

m is the slope

b is the intercept

Slope = 1+3/12+4

Slope = 4/16

Slope = 1/4

For the intercept

1 = 1/4(12) + b

b = 1 - 3

b = -2

Hence the equation in point slope form is y-1 = 1/4(x - 12)

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