2 years ago

NO LINKS!! Please help me with this problem

Mathematics

1 answer:

Anastaziya [24]2 years ago

7 0

Answer:

y²/324 -x²/36 = 1

Step-by-step explanation:

Where (0, ±b) are the ends of the transverse axis and y = ±(b/a)x describes the asymptotes, the equation of the hyperbola can be written as ...

y²/b² -x²/a² = 1

<h3>Application</h3>

Here, we have transverse axis endpoints of (0, ±18) and asymptotes of y = ±3x, so we can conclude ...

b = 18

b/a = 3 ⇒ a = 18/3 = 6

The equation of the hyperbola in standard form is ...

y²/324 -x²/36 = 1

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