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Agata [3.3K]
2 years ago
14

If x is normally distributed with U = 283 and o = 21 find p(x) is greater than 315

Mathematics
1 answer:
WINSTONCH [101]2 years ago
7 0

The probability that the value of p(x) is greater than 315 is 0.063754

<h3>How to determine the probability that the value of p(x) is greater than 315?</h3>

From the question, the given parameters about the distribution are

  • Mean value of the set of data = 283
  • Standard deviation value of the set of data = 21
  • The actual data value = 315

The z-score of the data value is calculated using the following formula

z = (x - mean value)/standard deviation

Substitute the given parameters in the above equation

z = (315 - 283)/21

Evaluate the difference of 315 and 283

z = 32/21

Evaluate the quotient of 32 and 21

z = 1.524

The probability that the value of p(x) is greater than 315 is then calculated as:

P(x > 315) = P(z > 1.524)

From the z table of probabilities, we have;

P(x > 315) = 0.063754

Hence, the probability that the value of p(x) is greater than 315 is 0.063754

Read more about probability at:

brainly.com/question/25870256

#SPJ1

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