Marlene lives in a building where half the residents live on the first floor and half live on the second floor. She wants to est
imate the probability that, out of 3 randomly selected residents, 1 or 2 live on the first floor.
She uses a coin to conduct a simulation, by letting H represent someone living on the first floor and T represent someone living on the second floor and then flipping the coin three times. She repeats this process for a total of 15 trials. The results are shown in the table.
Estimated probability that 1 or 2 of 3 randomly selected residents live on the first floor: ________
A.1/2
B.1/6
C.5/6
D.5/12
She uses a coin to conduct a simulation, by letting H represent someone living on the first floor and T represent someone living on the second floor and then flipping the coin three times. She repeats this process for a total of 15 trials. The results are shown in the table.
Estimated probability that 1 or 2 of 3 randomly selected residents live on the first floor: ________
A.1/2
B.1/6
C.5/6
D.5/12
2 answers:
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Answer:
The probability of his score being between 135 and 167 is 0.8151 or (0.8151*100=81.51%)
Step-by-step explanation:
Given that:
Mean = μ = 150
SD = σ = 12
Let x1 be the first data point and x2 the second data point
We have to find the z-scores for both data points
x1 = 135
x2 = 167
So,
And
We have to find area to the left of both points then their difference to find the probability.
So,
Area to the left of z1 = 0.1056
Area to the left of z2 = 0.9207
Probability to score between 135 and 167 = z2-z1 = 0.9027-0.1056 = 0.8151
Hence,
The probability of his score being between 135 and 167 is 0.8151 or (0.8151*100=81.51%)