Answer:
The correct option to the following question is CDO(Collateralized Debt Obligation).
Explanation:
CDO(collateralized debt obligations), is the financial tool that is used by the banks to repackage the individual loans into the product sold to the investors on secondary markets.
It developed as the instruments for corporate debts markets, after the year 2002, CDO became the vehicles for refinancing the mortgage backed the securities.
A CDO is the type of the structured asset backed security.
Answer:
The problem that created due to the difference in the model of programming language and the database model.
Explanation:
The practical relational model has three components which are as follows
1. Attributes
2. Datatypes
3. Tuples
To minimize this problem
1. We switch low pass L-Network to high pass L-network
2. We switch high pass L-Network to low pass L-network
3. We use the impedence matching transformer
Ummmm the solution is ummm brb
To avoid privacy these copyright is been implemented. If copyright is not implemented software company such as Microsoft, Google cannot run the organization so that software has copyright and licenses and they protect from software privacy.
<u>Explanation:</u>
Since the world is digital world all software are available in internet for download and end user will not pay for software and use the software without purchasing from software development industries.
Even software are protected with key, hacker write the tool to brakes the key, so end user easily use these tools and generate the key and user it.
So that software company use Digital millennium copyright act, so that end user can arrested for missing the software’s.
Answer:
Hi there! Please find the answer below.
Explanation:
The program below demonstrates how each of the requirements can be coded in a simple Python script. To copy the array, we can use the copy() method of the array. To calculate the diff, we can use a few different techniques, so I have implemented it using a loop over the arrays and just storing and displaying the difference in the 2 arrays.
new_string.py
def add_test_score(score):
test_score.append(score);
contact_hash = {}
test_score = []
print("Enter 5 test scores: ");
for x in range(0, 5):
input_string = input("Enter test score " + str(x + 1) + ": ")
add_test_score(int(input_string));
print(test_score);
test_score_copy = test_score.copy();
for e in test_score_copy:
if e < 60:
test_score_copy[test_score_copy.index(e)] += 10;
diff = [];
for e in test_score:
print(test_score[test_score.index(e)]);
print(test_score_copy[test_score.index(e)]);
if not test_score[test_score.index(e)] == test_score_copy[test_score.index(e)]:
diff.append(e);
print(diff);
