Answer:
None, drivers are hardware specific, if both devices share the same hadware manufacurer they tend to have the same drivers.
A driver is a software component that lets the operating system and a device communicate with each other. So asking for a difference in drivers is as asking the difference in hardware in both devices, though one tends to be more intergrated they are all the same in low level functions
Also drivers might not even communicate directly with the device but send a request. thats why some drivers can be written directly into an operating system.
I believe the correct answer from the choices listed above is option C. A credit limit is the maximum amount you can charge each billing cycle. <span>The </span>credit limit<span> on your credit card is the maximum balance your credit card issuer allows. Hope this answers the question.</span>
A cloud service providers uses KVM in their data centers because they are gravely concerned with insider threats.
KVM is a system for management, monitoring and control of a data center environment from a central location. In the data center this system is very necessary because the data center has multiple servers and computers. With this system the server can be connected and controlled from a remote location. This includes mapping the physical locations of accessible virtual drives.
Your question is incomplete, but most probably you full question was:
Modern managed cloud service providers will often use secure Keyboard/Video/Mouse (KVM) devices within their data centers. these devices are extremely expensive compared to their non-secured counterparts. which of the following is one of the reasons cloud service providers do this?
- They have plenty of revenue and can afford it
- They are gravely concerned with insider threats
- Cloud data centers need very few of these devices
- Managed cloud providers often manufacture their own devices as well
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Answer:
True: In binary search algorithm, we follow the below steps sequentially:
Input: A sorted array B[1,2,...n] of n items and one item x to be searched.
Output: The index of x in B if exists in B, 0 otherwise.
- low=1
- high=n
- while( low < high )
- { mid=low + (high-low)/2
- if( B[mid]==x)
- {
- return(mid) //returns mid as the index of x
- }
- else
- {
- if( B[mid] < x) //takes only right half of the array
- {
- low=mid+1
- }
- else // takes only the left half of the array
- {
- high=mid-1
- }
- }
- }
- return( 0 )
Explanation:
For each iteration the line number 11 or line number 15 will be executed.
Both lines, cut the array size to half of it and takes as the input for next iteration.
