B/h=3/8
8b=3h
8/3b=h
P=2(h+b)
P=138.6
138.6=2(h+b)
divide both sides by 2
69.3=h+b
suub (8/3)b for h
69.3=(8/3)b+b
times both sides by 3 to get rid of fraction
207.9=8b+3b
207.9=11b
divide both sides by 11
18.9=b
sub back
(8/3)b=h
(8/3)18.9=h
50.4=h
area=height times base
aera=50.4 times 18.9
aera=952.56 cm²
1. base=18.9 cm
2. height=50.4 cm
3. area=952.56 cm²
Hello again,
We know that the clock has rectangular shapes, and the clock face is circle.
Area of the clock is:
15×8=120 square inches
To find the area of the circle:
πr^2. However, we did not know the radius yet, but we had circumference of the circle which is 6 inches
C=2πr
6=2πr
Divided 2 from both side
3=πr
Divide π or 3.14 from both side
r≈1 inches
Area of the clock face is:
1×1×3.14
≈3.14.
To find the area of the clock that does not covered with clock face take:
120-3.14=116.86 square inches. Hope it help!
Answer:
It is true, except when x = 2/5, since it is an asymptote.
Step-by-step explanation:
3x=5xy-2y
3x=y(5x-2)
3x/5x-2=y
5x-2=0 -------> 5x=2 --------> x=2/5
Answer:
3x³ - 2x² is trinomial because highest degree of this polynomial is 3.
