Can anyone message me and help me out with some algebra 1 questions?

HEEEEEEEEEEELP <br> PLEEEEEEEEEASE

ollegr [7]

Answer:

y≥14

Step-by-step explanation:

Add 27 to both side so

y-27+27≥-13+27

so

y≥14

6 0

3 years ago

What are the solutions of the equation x6 + 6x3 + 5 = 0? Use factoring to solve.

lapo4ka [179]

Consider the equation $x^6+6x^3+5=0$ .

First, you can use the substitution $t=x^3$ , then $x^6=(x^3)^2=t^2$ and equation becomes $t^2+6t+5=0$ . This equation is quadratic, so

$D=6^2-4\cdot 5\cdot 1=36-20=16=4^2,\ \sqrt{D}=4,\\ \\ t_{1,2}=\dfrac{-6\pm 4}{2} =-5,-1$ .

Then you can factor this equation:

$(t+5)(t+1)=0$ .

Use the made substitution again:

$(x^3+5)(x^3+1)=0$ .

You have in each brackets the expression like $a^3+b^3$ that is equal to $(a+b)(a^2-ab+b^2)$ . Thus,

$x^3+5=(x+\sqrt[3]{5})(x^2-\sqrt[3]{5}x+\sqrt[3]{25}) ,\\x^3+1=(x+1)(x^2-x+1)$

and the equation is

$(x+\sqrt[3]{5})(x^2-\sqrt[3]{5}x+\sqrt[3]{25})(x+1)(x^2-x+1)=0$ .

Here $x_1=-\sqrt[3]{5} , x_2=-1$ and you can sheck whether quadratic trinomials have real roots:

1. $D_1=(-\sqrt[3]{5}) ^2-4\cdot \sqrt[3]{25}=\sqrt[3]{25} -4\sqrt[3]{25} =-3\sqrt[3]{25}$ .

2. $D_2=(-1)^2-4\cdot 1=1-4=-3$ .

This means that quadratic trinomials don't have real roots.

Answer: $x_1=-\sqrt[3]{5} , x_2=-1$

If you need complex roots, then

$x_{3,4}=\dfrac{\sqrt[3]{5}\pm i\sqrt{3\sqrt[3]{25}}}{2} ,\\ \\x_{5,6}=\dfrac{1\pm i\sqrt{3}}{2}$ .

6 0

3 years ago

The base area of a triangular pyramid is 22 square yards and the height of the pyramid is 15 yards. What is the volume of the tr

Vaselesa [24]

Answer:

110 yd cubed

Step-by-step explanation:

The volume of a triangular pyramid is denoted by: $V=\frac{1}{3} Bh$ , where B is the base area and h is the height. We already know here that B = 22 and h = 15, so we can just plug in these values:

$V=\frac{1}{3} *22*15=110$

Thus, the volume is 110 yards cubed.

Hope this helps!

8 0

3 years ago

Read 2 more answers

Conner scored 4,370 points in a game.Amy scored 1,089 fewer points then Conner how many points did Amy scored

statuscvo [17]

SOLUTION:

Connor's score = 4, 370 points

Amy's score = Connor's score - 1, 089

Amy's score = 4, 370 - 1089

Amy's score = 3, 281 points

Therefore, Amy scored 3, 281 points.

Hope this helps! :)
Have a lovely day! <3

3 0

3 years ago

MATH HELP???

marin [14]

<h2>Answer:</h2>

The quadratic function are:

option: A A) y(y + 4) - y = 6

Option: C C.) 4b(b) = 0

<h2>Step-by-step explanation:</h2>

We know that the general equation of a quadratic equation in terms of a variable x is given by:

$ax^2+bx+c=0$

A)

y(y + 4) - y = 6

On simplifying the terms we have:

$y^2+4y-y=6\\\\y^2+3y-6=0$

Hence, option: A is correct.

B)

(3x + 2) + (6x - 1) = 0

$(3x + 2) + (6x - 1) = 0\\\\i.e.\\\\3x+2+6x-1=0\\\\i.e.\\\\3x+6x+2-1=0\\\\i.e.\\\\9x+1=0$

Hence, it is a linear equation.

Hence, option: B is incorrect.

C)

4b(b) = 0

it could also be written as:

$4b^2=0$

Hence, it is a quadratic equation.

Hence, option: C is correct.

D)

3a - 7 = 2(7a - 3)

$3a-7 = 2(7a-3)\\\\i.e.\\\\3a-7=14a-6\\\\\\i.e.\\\\14a-6-3a+7=0\\\\i.e.\\\\14a-3a-6+7=0\\\\i.e.\\\\11a+1=0$

which is again a linear equation.

Hence, option: D is incorrect.

6 0

3 years ago