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Aleksandr-060686 [28]
2 years ago
12

I need help!!!!!!!!!!!!!! how many pound are in 40 ounces. this is off or i ready. please help me!!!

Mathematics
2 answers:
Sergeeva-Olga [200]2 years ago
7 0
2.5 is the answer. Divide the mass value (40) by 16 to find out the answer. Example: Mass value / 16 = X
kogti [31]2 years ago
6 0

Answer:

2.5 pounds

Step-by-step explanation:

You might be interested in
4
melamori03 [73]

Answer:

Area = 16sq inches

Perimeter =  16 inches

Step-by-step explanation:

The shape of body is a square:

 Area = S²

 Perimeter = 4S

S is the side length

So;

      S  = 4inches

Therefore;

       Area = S²   = 4²   = 16sq inches

       Perimeter  = 4S  = 4(4)  = 16inches

7 0
3 years ago
Read 2 more answers
What is the area of the triangle above
VladimirAG [237]
I am pretty sure the answer is 17.5
Step by step:
5x7=35
35/2=17.5
5 0
3 years ago
Simplify: 40x7- (-12x7)<br> Enter the original expression if it cannot be<br> simplified.
fredd [130]

Answer:

52x^7

Step-by-step explanation:

40x^7 -(-12x^7) =

= 40x^7 + 12x^7 =

= 52x^7

Hope this helps!

If not, I am sorry.

Please mark brainliest if correct!

5 0
2 years ago
Gavin earned $253.00 at his job when he worked for 11 hours. How much money did he earn each hour?​
denis23 [38]

Answer:

$23.00 Every Hour :)

Step-by-step explanation:

So, in a type of question like this what you would have to do is divide. You can use a calculator or do the long division yourself. The equation would be 253 divided by 11. How many times does 11 go into 253? 23. Then, that's your final answer.

3 0
3 years ago
Read 2 more answers
Suppose that the function u and w are defined as follows.
mars1129 [50]

That funky circle in the middle is the composition of the function. It asks you to take a function as an input and to yield an output that's another function. It's one of the five function operations, along with adding, subtracting, multiplying, and dividing.

When you compose, you might find the notation w(u(x)) easier to understand. It's saying evaluate u then evaluate w.

For our functions, the compositions are:

u(w(x)) = u(2x²) = -(2x²) - 2 = -2x² - 2

w(u(x)) = w(-x - 2) = 2(-x - 2)² = 2(x² + 4x + 4) = =2x²+ 8x +8

Now we evaluate each composition at 4.

u(w(4)) = -2(4²) - 2 = -2(16) - 2 = -32 -2 = -34

w(u(4)) = -2(2²) +8(2) + 8 = -2(4) + 16 + 8 = -8 + 16 + 8 = 16.

Thus, u(w(4)) = -34 and w(u(4)) = 16.

5 0
3 years ago
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