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2 years ago

Brand X costs $2.70 for 10 ounces. Brand Y costs 4 cents more per ounces. What is the cost of 11 ounces of brand Y?

1 answer:

8 0

Well you have to first find the constant of Brand X which would be 2.70/10 = .27. Brand Y is .4 more so that would be .31 per ounce. So then .31 x 11 = 3.41. The cost of 11 ounces of brand Y is $3.41.

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A publisher needs to send many books to a local book retailer, and will send the books in a combination of small and large boxes

KonstantinChe [14]

Answer:

415 books, I dont understand the second question, sorry

Step-by-step explanation:

1 small box=20 books

1 big box=45 books

5 small boxes×20 books= 100 books

7 large boxes×45 books= 315 books

315 books+100 books=415 books

8 0

3 years ago

Read 2 more answers

HELP HELP WILL MARK BRAINLIEST

SashulF [63]

Answer:

b. 10a³ - 11a - 3

Step-by-step explanation:

1. Expand 3(a³ - 2a - 5)

= 3a³ - 6a - 15

2. Add 7a³ - 5a + 12 and 3a³ - 6a - 15

7a³ + 3a³ = 10a³

-5a + -6a = -11a

12 + -15 = -3

3. Answer: b. 10a³ - 11a - 3

4 0

2 years ago

Kayla is running for charity. Her dad pledges to give her $0.50 per mile she runs. Her mom pledges to give her a flat donation o

amm1812

Answer:

10 miles

Step-by-step explanation:

Let m represent the number of miles Kayla runs. We want to find m such that ...

0.50m = 5.00

Divide by the coefficient of m:

m = 5.00/0.50 = 10

Kayla has to run 10 miles to get the same donation from both parents.

5 0

3 years ago

14. NUTRITION A cookie contains 9 grams of fat. If you eat no fewer than 4 and no more than 7 cookies, how many grams of fat wil

ra1l [238]

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8 0

2 years ago

Solve the equation (linear equation)<br><br> <img src="https://tex.z-dn.net/?f=8%5E%7B2x%2B7%7D%20%3D%20%28%5Cfrac%7B1%7D%7B32%7

Minchanka [31]

Answer: $x=-1$

Step-by-step explanation:

By the negative exponent rule, you have that:

$(\frac{1}{a})^n=a^{-n}$

By the exponents properties, you know that:

$(m^n)^l=m^{(nl)}$

Therefore, you can rewrite the left side of the equation has following:

$(\frac{1}{8})^{-(2x+7)}=(\frac{1}{32})^{3x}$

Descompose 32 and 8 into its prime factors:

$32=2*2*2*2*2=2^5\\8=2*2*2=2^3$

Rewrite:

$(\frac{1}{2^3})^{-(2x+7)}=(\frac{1}{2^5})^{3x}$

Then:

$(\frac{1}{2})^{-3(2x+7)}=(\frac{1}{2})^{5(3x)}$

As the base are equal, then:

$-3(2x+7)=5(3x)$

Solve for x:

$-6x-21=15x\\-21=15x+6x\\-21=21x\\x=-1$

8 0

3 years ago