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Oxana [17]
2 years ago
12

Select all of the following problem situations that involve permutations. How many ways can you arrange 4 of the letters of the

word SOLVE if no letter can be used more than once
Mathematics
1 answer:
Nikolay [14]2 years ago
7 0

There are 24 ways in which we can arrange 4 letters of the word "SOLVE" if no letter can be used more than once.

Given a word of 4 letters of the word "SOLVE".

We are required to find the number of ways the four letters of the word SOLVE if no letter can be used more than once.

Permutation is an arrangement of objects in a definite order of things.

Factorial of a number is the product of it and its lesser numbers upto 1.

Number of letters=4

Number of ways=4!

=4*3*2*1

=24 ways

Hence there are 24 ways in which we can arrange 4 letters of the word "SOLVE" if no letter can be used more than once.

Learn more about factorial at brainly.com/question/25997932

#SPJ4

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Point A is the midpoint of side XZ and point B is the
Katyanochek1 [597]

Answer:

Option (2)

Step-by-step explanation:

Given question is incomplete; here is the complete question.

Point A is the midpoint of side XZ and point B is the  midpoint of side YZ.

Triangle XYZ is cut by line segment AB. Point A is the midpoint of side XZ and point B is the midpoint of side YZ. The length of XY is (5x - 7), the length of AB is (x + 1), and the lengths of XA and ZA are (2x - 2). The lengths of YB and BZ are congruent.

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2 units

4 units

6 units

8 units

From the figure attached,

XYZ is a triangle having A and B as the midpoints of the sides XZ and YZ.

By the theorem of midpoints,

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Since AB = (x + 1) and XY = (5x - 7)

(x + 1) = \frac{1}{2}(5x-7)

2x + 2 = 5x - 7

5x - 2x = 2 + 7

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Therefore, side AB = 3 + 1 = 4 units

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Side XA = 2(x - 1)

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What is the equation of the perpendicular bisector of CB?
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