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anyanavicka [17]
3 years ago
5

If EG=19 and FG=12 then EF=?

Mathematics
1 answer:
Volgvan3 years ago
3 0

Answer:

EF = 31

Step-by-step explanation:

Note that in both line segments (EG & FG), they both have point G in them. This means that point G is the shared point and the mid-point. Add the two line segments together to get the full segment.

EG + FG = EF

19 + 12 = 31

31 is your answer

~

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PLZ HELP I WILL GIVE BRAINLIEST:
prohojiy [21]

The average rate of change for the function f(x)= 3^x + 25 using the intervals of x=2 to x=6 is 6.75

The function is given as:

f(x) = 3^x + 25

The interval is given as:

x = 2 to 6

Start by calculating f(2) and f(6)

f(2) = 3^2 + 25 = 34

f(6) = 6^2 + 25 = 61

The average rate of change is then calculated as:

m = \frac{f(6) - f(2)}{6 -2}

This gives

m = \frac{61 - 34}{6 -2}

m = \frac{27}{4}

m = 6.75

Hence, the average rate of change is 6.75

Read more about average rate of change at:

brainly.com/question/8728504

8 0
2 years ago
Use Random number generator and simulate 1000 long columns, for each of the three cases. Example: for the Car type 1, use Number
sertanlavr [38]

Answer:

Step-by-step explanation:

The question is incomplete since they do not give information about the Car type 3.

We will do it in a generic way, we will say that the Car type 3 has a mean of M and a standard deviation SD.

We would be:

P (CT3 <550) = P [z <(550 - X) / SD]

Now if we give it values, for example that X = 600 and SD = 120

It would remain:

P (CT3 <550) = P [z <(550 - 600) / 120]

P (CT3 <550) = P [z <-0.42]

We look for this value in the normal distribution table (attached) and it shows us that the probability is approximately 0.3372, that is, 33.72%

What you need to do is replace the X and SD values of theCar type 3 in the equation above how I just did and you will get the result.

7 0
3 years ago
Can someone help me for brainliest
Nataly [62]

Answer:

10)

No. Since the garage is a square, the length and width are the same. And since the formula to find the area of a square is (length times width) l x w , that means that the square root of 121 would be the length and width of the garage. The square root of 121 is 11, concluding that the car that measures 13 feet long is too large.

11)

7. its the square root of 49, which is the closest to 55.

hope this helps!

5 0
3 years ago
Katlin divided a fraction by 1/2 the result was a mixed number. was the fraction less than or greater than 1/2? EXPLAIN.
julsineya [31]
The fraction was greater than 1/2.

When you divide by a fraction, it is equal to multiplying by its reciprocal. The reciprocal of 1/2 is 2/1, or just 2. Therefore, dividing by 1/2 equals the same thing as when you multiply by 2.

A mixed number has a whole number and a fraction added together. So, the mixed number must be greater than 1.

1/2 is equal to 0.5, and 0.5 multiplied by 2 equals 1. A fraction less than 1/2 multiplied by 2 would equal a number less than 1, while a fraction greater than 1/2 would equal a number greater than 1.

Because a mixed number must be greater than 1, and a fraction greater than 1/2 multiplied by 2 would be greater than 1, the fraction that resulted in a mixed number after being multiplied by 2 must have been greater than 1/2.
5 0
3 years ago
How can I reflect this horizontally without a value for h?
Alex_Xolod [135]

Answer:

Another transformation that can be applied to a function is a reflection over the x– or y-axis. A vertical reflection reflects a graph vertically across the x-axis, while a horizontal reflection reflects a graph horizontally across the y-axis. The reflections are shown in Figure 9.

Graph of the vertical and horizontal reflection of a function.

Figure 9. Vertical and horizontal reflections of a function.

Notice that the vertical reflection produces a new graph that is a mirror image of the base or original graph about the x-axis. The horizontal reflection produces a new graph that is a mirror image of the base or original graph about the y-axis.

A GENERAL NOTE: REFLECTIONS

Given a function \displaystyle f\left(x\right)f(x), a new function \displaystyle g\left(x\right)=-f\left(x\right)g(x)=−f(x) is a vertical reflection of the function \displaystyle f\left(x\right)f(x), sometimes called a reflection about (or over, or through) the x-axis.

Given a function \displaystyle f\left(x\right)f(x), a new function \displaystyle g\left(x\right)=f\left(-x\right)g(x)=f(−x) is a horizontal reflection of the function \displaystyle f\left(x\right)f(x), sometimes called a reflection about the y-axis.

HOW TO: GIVEN A FUNCTION, REFLECT THE GRAPH BOTH VERTICALLY AND HORIZONTALLY.

Multiply all outputs by –1 for a vertical reflection. The new graph is a reflection of the original graph about the x-axis.

Multiply all inputs by –1 for a horizontal reflection. The new graph is a reflection of the original graph about the y-axis.

EXAMPLE 7: REFLECTING A GRAPH HORIZONTALLY AND VERTICALLY

Reflect the graph of \displaystyle s\left(t\right)=\sqrt{t}s(t)=√

t

(a) vertically and (b) horizontally.

SOLUTION

a. Reflecting the graph vertically means that each output value will be reflected over the horizontal t-axis as shown in Figure 10.

Graph of the vertical reflection of the square root function.

Figure 10. Vertical reflection of the square root function

Because each output value is the opposite of the original output value, we can write

\displaystyle V\left(t\right)=-s\left(t\right)\text{ or }V\left(t\right)=-\sqrt{t}V(t)=−s(t) or V(t)=−√

t

Notice that this is an outside change, or vertical shift, that affects the output \displaystyle s\left(t\right)s(t) values, so the negative sign belongs outside of the function.

b.

Reflecting horizontally means that each input value will be reflected over the vertical axis as shown in Figure 11.

Graph of the horizontal reflection of the square root function.

Figure 11. Horizontal reflection of the square root function

Because each input value is the opposite of the original input value, we can write

\displaystyle H\left(t\right)=s\left(-t\right)\text{ or }H\left(t\right)=\sqrt{-t}H(t)=s(−t) or H(t)=√

−t

Notice that this is an inside change or horizontal change that affects the input values, so the negative sign is on the inside of the function.

Note that these transformations can affect the domain and range of the functions. While the original square root function has domain \displaystyle \left[0,\infty \right)[0,∞) and range \displaystyle \left[0,\infty \right)[0,∞), the vertical reflection gives the \displaystyle V\left(t\right)V(t) function the range \displaystyle \left(-\infty ,0\right](−∞,0] and the horizontal reflection gives the \displaystyle H\left(t\right)H(t) function the domain \displaystyle \left(-\infty ,0\right](−∞,0].

TRY IT 2

Reflect the graph of \displaystyle f\left(x\right)=|x - 1|f(x)=∣x−1∣ (a) vertically and (b) horizontally.

Solution

EXAMPLE 8: REFLECTING A TABULAR FUNCTION HORIZONTALLY AND VERTICALLY

A function \displaystyle f\left(x\right)f(x) is given. Create a table for the functions below.

\displaystyle g\left(x\right)=-f\left(x\right)g(x)=−f(x)

\displaystyle h\left(x\right)=f\left(-x\right)h(x)=f(−x)

\displaystyle xx 2 4 6 8

\displaystyle f\left(x\right)f(x) 1 3 7 11

SOLUTION

For \displaystyle g\left(x\right)g(x), the negative sign outside the function indicates a vertical reflection, so the x-values stay the same and each output value will be the opposite of the original output value.

\displaystyle xx 2 4 6 8

\displaystyle g\left(x\right)g(x) –1 –3 –7 –11

For \displaystyle h\left(x\right)h(x), the negative sign inside the function indicates a horizontal reflection, so each input value will be the opposite of the original input value and the \displaystyle h\left(x\right)h(x) values stay the same as the \displaystyle f\left(x\right)f(x) values.

\displaystyle xx −2 −4 −6 −8

\displaystyle h\left(x\right)h(x) 1 3 7 11

TRY IT 3

\displaystyle xx −2 0 2 4

\displaystyle f\left(x\right)f(x) 5 10 15 20

Using the function \displaystyle f\left(x\right)f(x) given in the table above, create a table for the functions below.

a. \displaystyle g\left(x\right)=-f\left(x\right)g(x)=−f(x)

b. \displaystyle h\left(x\right)=f\left(-x\right)h(x)=f(−x)

3 0
2 years ago
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