Do the data support or refute the hypothesis, normally, the data for the first part of the experiment support the first hypothesis.
<h3>What is a hypothesis test?</h3>
Hypothesis testing refers to the formal procedures used by statisticians to accept or reject these hypotheses. When trying to make decisions, it is convenient to formulate assumptions or conjectures about the populations of interest, which consist of considerations about their parameters.
As a result of this, we can see that from the complete text, there is a set of data which is used to show the force that is applied to a cart that causes the acceleration of the cart to increase which supports Newton's second law.
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Answer:
Part a)
Part b)
Explanation:
As we know that the electric field between the membrane is given as
here the distance between two membranes is given as
now we know that potential difference between two membranes is given as
so we have
Part b)
Kinetic energy of helium nucleus is given as
so we have
Answer:
Proxima Centauri is a small, low-mass star located 4.244 light-years (1.301 pc) away from the Sun in the southern constellation of Centaurus. Its Latin name means the "nearest [star] of Centaurus". This object was discovered in 1915 by Robert Innes and is the nearest-known star to the Sun.
Star system: Alpha Centauri
Category: Star, Flare star
Constellation: Centaurus
Discoverer: Robert T. A. Innes
Explanation:
u should make it into an essay
See the attached figure.
The black arrows represent the two given vectors. The dashed black arrows are these same vectors, but translated so that the end of one vector is aligned with the start of another.
The red vector is their sum.
In case you also need to find the magnitude and direction of the sum, we have
A = (120 N) (cos(30°) i + sin(30°) j) = (60√3 i + 60 j) N
B = (-100 N) (cos(90°) i + sin(90°) j) = (-100 j) N
⇒ A + B = (60√3 i - 40 j) N
⇒ ||A + B|| = √((60√3)² + (-40)²) N = 20√31 N
and its direction relative to the positive horizontal axis (rightward) is θ such that
tan(θ) = (-40) / (60√3) = -2/(3√3)
⇒ θ = arctan(-2/(3√3)) ≈ -21.05°