as it is given that it covers a total distance 1 * 10^2 m
total time taken by it = 13.6 s
now the average speed is given as ratio of total distance and total time



so the average speed will be 7.35 m/s
now if it starts from rest and achieve the final speed as 7.35 m/s
now we can use kinematics



so its acceleration will be 3.68 m/s^2
Answer:
the <em>ratio F1/F2 = 1/2</em>
the <em>ratio a1/a2 = 1</em>
Explanation:
The force that both satellites experience is:
F1 = G M_e m1 / r² and
F2 = G M_e m2 / r²
where
- m1 is the mass of satellite 1
- m2 is the mass of satellite 2
- r is the orbital radius
- M_e is the mass of Earth
Therefore,
F1/F2 = [G M_e m1 / r²] / [G M_e m2 / r²]
F1/F2 = [G M_e m1 / r²] × [r² / G M_e m2]
F1/F2 = m1/m2
F1/F2 = 1000/2000
<em>F1/F2 = 1/2</em>
The other force that the two satellites experience is the centripetal force. Therefore,
F1c = m1 v² / r and
F2c = m2 v² / r
where
- m1 is the mass of satellite 1
- m2 is the mass of satellite 2
- v is the orbital velocity
- r is the orbital velocity
Thus,
a1 = v² / r ⇒ v² = r a1 and
a2 = v² / r ⇒ v² = r a2
Therefore,
F1c = m1 a1 r / r = m1 a1
F2c = m2 a2 r / r = m2 a2
In order for the satellites to stay in orbit, the gravitational force must equal the centripetal force. Thus,
F1 = F1c
G M_e m1 / r² = m1 a1
a1 = G M_e / r²
also
a2 = G M_e / r²
Thus,
a1/a2 = [G M_e / r²] / [G M_e / r²]
<em>a1/a2 = 1</em>
The atomic mass of an atom ... in Atomic Mass Units ... is the sum of the numbers of protons and neutrons in its nucleus.
(4) Elevations:
Point A: 900 ft
Point B: 900 ft
Point C: 1500 ft
Point D: 1000 ft
(5) Contour interval: 100 ft
(6) Plot #1 best fits the profile seen in the contour map.
Answer:
two-slit interference model was proposed by Young d sin θ = m λ
Explanation:
The two-slit interference model was proposed by Young, it establishes that if a coherent source of light passes through two slits, the shape of the given pattern is a consequence of the relative phase difference between the two rays; mathematically it can be expressed by
d sin θ = m λ
m= 0, 1, 2, 3, ...
for constructive interference, that is, the two rays arrive with a number between wavelengths.
D is the distance between the slits, tea the angle between the two rays, m an integer and m the wavelength used.
In a simulation a pattern of slits of equal intensity and equally spaced is observed.