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3 years ago

What would happen to moon if gravity no longer affected it?

Physics

2 answers:

Tatiana [17]3 years ago

8 0

Answer: The moon would continue to move on its orbital path.

Explanation:

bulgar [2K]3 years ago

7 0

Without the force of gravity from the Earth, it would just float away into space. This mix of velocity and distance from the Earth allows the Moon to always be in balance between fall and escape. If it was faster, it would escape; any slower and it would fall.

Also - A missing moon could cause even more disruptive changes, although on a much longer time scale. Without the moon's gravity holding the Earth in place, the tilt of our home planet's axis would probably shift drastically over time It has no large, stabilizing moon to stop it

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A magnesium surface has a work function of 2.65 eV. Electromagnetic waves with a wavelength of 280 nm strike the surface and eje

Neko [114]

Answer:

Explanation:

Energy of radiation in eV = 1237.5/280 = 4.42 eV.

Work function = 2.65 eV.

Maximum kinetic energy = 4.42 - 2.65 = 1.77 eV.

8 0

4 years ago

A ray of monochromatic light ( f = 5.09 × 10^14 Hz) passes from air into Lucite at an angle

harina [27]

Let us consider the air with the index 1 and the lucite with index 2. Using the Snell's Secound Law, we have:

$\frac{sen\O_{2}}{sen\O_{1}} = \frac{n_{2}}{n_{1}} \\ sen\O_{2}= \frac{n_{2}*sen\O_{1}}{n_{1}}$

Entering the unknowns, remembering that the air refrective index is 1 and the lucite refrective index is 1.5, comes:

$sen\O_{2}= \frac{n_{2}*sen\O_{1}}{n_{1}} \\ sen\O_{2}= \frac{1.5* \frac{1}{2} }{1} \\ sen\O_{2}=0.75$

Using the arcsin properties, we get:

$sen\O_{2}=0.75 \\ arcsin(0.75)=\O_{2} \\ \boxed {\O_{2}=48.59^o}$

Obs: Approximate results, and the drawing is attached

If you notice any mistake in my english, let me know, because i am not native.

6 0

3 years ago

Un motor realiza un trabajo de 5000 j en 20 s a) ¿ cual es la potencia del motor ?B)¿en cuanto tiempo desarollan el mismo trabaj

zimovet [89]

Answer:

a. Potencia = 250 Watts

b. Tiempo = 333.33 segundos

Explanation:

Dados los siguientes datos;

Energía = 5000 Joules

Tiempo = 20 segundos.

Para encontrar el poder;

Poder = energía/tiempo

Potencia = 5000/20

Potencia = 250 Watts

B. ¿Para saber cuánto tarda una máquina en realizar el mismo trabajo;

Dado: potencia = 15 W

Tiempo = energía/poder

Tiempo = 5000/15

Tiempo = 333.33 segundos

3 0

3 years ago

2. An object with a mass of 3.8 kg has four forces acting on it.

marshall27 [118]

Answer:4.7N

Explanation:both of the sides are equal

7 0

3 years ago

1.What type of sediment forms from minerals that crystallize from seawater?

nikdorinn [45]

The correct answers are as follows:
<span>1) hydrogenous sediment

2)sand and gravel

3) They rapidly break down at surface temperatures and pressures.</span>

7 0

3 years ago

Read 2 more answers