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weqwewe [10]
3 years ago
6

What would happen to moon if gravity no longer affected it?

Physics
2 answers:
Tatiana [17]3 years ago
8 0

Answer: The moon would continue to move on its orbital path.

Explanation:

bulgar [2K]3 years ago
7 0
Without the force of gravity from the Earth, it would just float away into space. This mix of velocity and distance from the Earth allows the Moon to always be in balance between fall and escape. If it was faster, it would escape; any slower and it would fall.

Also - A missing moon could cause even more disruptive changes, although on a much longer time scale. Without the moon's gravity holding the Earth in place, the tilt of our home planet's axis would probably shift drastically over time It has no large, stabilizing moon to stop it
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What is the characteristic of a Matrix Transpose
yulyashka [42]

Answer:

columns are converted into rows , and rows are converted into columns

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4 years ago
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sdas [7]

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8 0
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Calculate the gravitational potential energy of a body of mass 40 kg at a vertical height of 10 m. ( g = 9.8 m/s2)
olganol [36]
Ep= mgh
Ep = 40 x 9.8 x 10
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8 0
3 years ago
A tomato of mass 0.18 kg is dropped from a tall bridge. If the tomato has a speed of 11 m/s just before it hits the ground, what
kondor19780726 [428]
The kinetic energy of the tomato is : 

K.E =  1/2 mv^2

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7 0
3 years ago
The magnetic field inside a superconducting solenoid is 4.00 T. The solenoid has an inner diameter of 6.20 cm and a length of 26
Delvig [45]

Answer:

(a) The magnetic energy density in the field is 6.366 J/m³

(b) The energy stored in the magnetic field within the solenoid is 5 kJ

Explanation:

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inner diameter of solenoid, d = 6.2 cm

inner radius of the solenoid, r = 3.1 cm = 0.031 m

length of solenoid, L = 26 cm = 0.26 m

(a) The magnetic energy density in the field is given by;

u _B = \frac{B^2}{2\mu_o} \\\\u _B = \frac{(4)^2}{2(4\pi*10^{-7})}\\\\u_B = 6.366*10^6 \ J/m^3

(b) The energy stored in the magnetic field within the solenoid

U_B = u_B V\\\\U_B = u_B AL

U_B = u_B(A)(L)\\\\U_B = 6.366*10^6(\pi * 0.031^2)(0.26) \\\\U_B = 4997.69 J\\\\U_B = 5 \ KJ\\

6 0
3 years ago
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