Question

The lateral surface area of cone A is exactly 1/2 the lateral surface area of cylinder B. Cone A radius is r and height h - Cylinder B radius is r and height h. True or false?

Answer 1

The ratio of the lateral surface area of cone A to the lateral surface area of cylinder B is equal to $r = \frac{1}{2}\cdot \frac{\sqrt{r^{2}+h^{2}}}{h}$. (Correct choice: False)

What is the ratio of lateral area of cone to the lateral area of the cylinder?

In accordance with space geometry, the lateral areas of the cone and cylinder are described by the following equations:

Cone

$A_{l} = \pi \cdot r \cdot \sqrt{r^{2}+h^{2}}$     (1)

Cylinder

$A_{l} = 2\pi\cdot r\cdot h$     (2)

If we divide (2) by (1), then we have the following ratio:

$r = \frac{1}{2}\cdot \frac{\sqrt{r^{2}+h^{2}}}{h}$

The ratio of the lateral surface area of cone A to the lateral surface area of cylinder B is equal to $r = \frac{1}{2}\cdot \frac{\sqrt{r^{2}+h^{2}}}{h}$. (Correct choice: False)

To learn more on surface areas: brainly.com/question/2835293

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