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aleksklad [387]
2 years ago
12

Jack tried to define a rotation.For the center point CCC, the image C'C ′ C, prime is at the same point as CCC. For a point PPP

that is not at CCC, a rotation of \thetaθtheta about point CCC creates point P'P ′ P, prime, such that CP=CP'CP=CP C, P, equals, C, P, prime and m\angle PCP'=\thetam∠PCP ′=θm, angle, P, C, P, prime, equals, theta. What mistake did Jack make in his definition of a rotation?
A
Jack needed to include the direction of the rotation.

(Choice B)
B
m\angle CPP'm∠CPP
′
m, angle, C, P, P, prime must equal \thetaθtheta.

(Choice C)
C
Point CCC must be the midpoint of PP'PP
′
P, P, prime.

(Choice D)
D
Jack did not make a mistake.
Mathematics
2 answers:
Harrizon [31]2 years ago
8 0
I think it’s B hope that helps
andriy [413]2 years ago
7 0
The answer is A because jack needs to find the point of ccc no i don’t want to get up to me and you
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if PQ || RS and the slope of PQ= x-1/4 and the slope of RS is 3/8 then find the value of x justify algebraically and numerically
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The value of x is 5/8.

<u>Step-by-step explanation</u>:

Given,

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The slopes of parallel lines are equal.

slope of PQ = slope of RS

⇒ x-1/4 = 3/8

⇒ (4x-1)/4 = 3/8

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5 0
3 years ago
(cotx+cscx)/(sinx+tanx)
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Answer:   \bold{\dfrac{cot(x)}{sin(x)}}

<u>Step-by-step explanation:</u>

Convert everything to "sin" and "cos" and then cancel out the common factors.

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\text{Simplify:}\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)+sin(x)}{cos(x)}\bigg)\\\\\\\text{Multiply by the reciprocal (fraction rules)}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)cos(x)+sin(x)}\bigg)\\\\\\\text{Factor out the common term on the right side denominator}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)(cos(x)+1)}\bigg)

\text{Cross out the common factor of (cos(x) + 1) from the top and bottom}:\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)}\bigg)\\\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times cot(x)}\qquad \rightarrow \qquad \dfrac{cot(x)}{sin(x)}

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Step-by-step explanation:

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