Select the correct answer. Given the following formula, solve for a. A. B. C. D. s=a+b+C/2

Mathematics

1 answer:

nexus9112 [7]3 years ago

7 0

Hey there!

The answer to your question is a = s - b - C/2

To solve for "a", we must get "a" on it's own side of the equal sign. We can first subtract "s" from both sides:

0 = a + b + C/2 - s

Then, we can subtract a from both sides:

-a = b + C/2 - s

Finally, we divide both sides by -1, so a is by itself.

a = -b - C/2 + s

And we can rearrange it to the standard form:

a = s - b - C/2

Good luck, and hope it helped! Have a great day!

You might be interested in

Number 6 and 7 what is the answer please!

larisa [96]

6. 40 minutes (15/3 = 5 minutes/mile) - 5*8 = 40 min
7. 15,840 ft / 5 = 3.168 ft

5 0

3 years ago

Read 2 more answers

A=444 b=213. 4÷a×b= can you help me plz

Lelechka [254]

First, let's input "a" and "b" into the equation:
(Don't forget to put brackets around the inputted numbers to show you are inputting "a" and "b")

4 ÷ a × b = 4 ÷ (444) x (213)

Now we can solve!

= 1.918
= ~ 2

Hope this helps!
Feel free to message me if you have any questions :)

5 0

3 years ago

Betty had 1/3 yard of ribbon. She used 1/2 of it. How many yards of ribbon did she use?

Charra [1.4K]

Answer:

b. 1/6 yd

Step-by-step explanation:

When Betty used 1/2 OF the 1/3 yards she has she has to multiple those. It's easier to put it in a sentence in my opinion because then you can see the "of" in the sentence which means to multiply. Hope this helps!

6 0

3 years ago

What is the average rate of change if this function interval x = -3 to x = 0

jok3333 [9.3K]

The average rate of change of the function, over the given interval is 2.

This question is incomplete, the complete question is:

What is the average rate of change of f(x) = 2x+10, if this function interval are x = -3 to x = 0.

<h3>What is the average rate of change over the interval?</h3>

The average rate of change of f(x) over the interval [a,b] is expressed as;

$\frac{f(b)-f(a)}{b-a}$

Given that;

f(x) = 2x + 10
Interval: [ -3, 0 ], a = -3 and b = 0

We substitute our values into the expression above.

$\frac{f(b)-f(a)}{b-a}\\\\\frac{f(0)-f(-3)}{0-(-3)}\\\\\frac{[2(0)+10]-[2(-3)+10]}{0-(-3)}\\\\\frac{[10]-[-6+10]}{3}\\\\\frac{[10]-[4]}{3}=\frac{6}{3}=2$