Answer:
0.630
Step-by-step explanation:
Simply evaluating, we get v (0) = 1, v (0.31831) = 0.630, v (2) = 1.566. Thus, the minimum velocity over the interval [ 0, 2] is 0.630.
Answer:
see below
Step-by-step explanation:

find common denominator and add the fractions in numerator and denominator:
1/x² + 2/y = y+2x²/x²y
5/x -6/y² =5y² -6x/xy²
(y+2x²)/x²y / (5y²-6x)/xy² change into multiplication
(y+2x²)/x²y * xy²/(5y²-6x)
simplify
y(y+2x²)/ x(5y²-6x)
Answer:
<h3>Graph 3</h3>
Line starting at x = -2
- <u>Domain</u>: x ≥ -2
- <u>Range</u>: y ≥ 0
<h3>Graph 4</h3>
Vertical line
- <u>Domain</u>: x = 3
- <u>Range</u>: y = any real number
<h3>Graph 5</h3>
Quadratic function with negative leading coefficient and max value of 3
- <u>Domain</u>: x = any real number
- <u>Range</u>: y ≤ 3
<h3>Graph 6</h3>
Curve with non-negative domain and min value of -2
- <u>Domain</u>: x ≥ 0
- <u>Range</u>: y ≥ -2
<h3>Graph 7</h3>
Line with no restriction
- <u>Domain</u>: x = any real number
- <u>Range</u>: y = any real number
<h3>Graph 8</h3>
Quadratic function with positive leading coefficient and min value of 4
- <u>Domain</u>: x = any real number
- <u>Range</u>: y ≥ 4
<h3>Graph 9</h3>
Parabola with restriction at x = -4
- <u>Domain</u>: x = any real number except -4
- <u>Range</u>: y = any real number
<h3>Graph 10</h3>
Square root function with star point (2, 0)
- <u>Domain</u>: x ≥ 2
- <u>Range</u>: y ≥ 0