Answer:
(2.8, 0.8)
(0.8, -1.8)
Step-by-step explanation:
1. Home (Xa, Ya)= (8, 6)
San Antonio (Xb, Yb)=(-5, -7)
Xa-Xb=8-(-5)=13
Ya-Yb=6-(-7)=13
Emily starts at 2/5 of the road, make it (Xc, Yc)
Xc= Xa-(Xa-Xb)2/5=8-5.2=2.8
Yc=Ya-(Ya-Yb)2/5=6-5.2=0.8
=> Emily starts at (2.8, 0.8)
2.
Emily ends at 3/5 of the road, , make it (Xd, Yd)
Xd= Xa-(Xa-Xb)3/5=8-7.8=0.8
Yd=Ya-(Ya-Yb)3/5=6-7.8=-1.8
=> Emily ends at (0.8, -1.8)
Answer:
1. Objective function is a maximum at (16,0), Z = 4x+4y = 4(16) + 4(0) = 64
2. Objective function is at a maximum at (5,3), Z=3x+2y=3(5)+2(3)=21
Step-by-step explanation:
1. Maximize: P = 4x +4y
Subject to: 2x + y ≤ 20
x + 2y ≤ 16
x, y ≥ 0
Plot the constraints and the objective function Z, or P=4x+4y)
Push the objective function to the limit permitted by the feasible region to find the maximum.
Answer: Objective function is a maximum at (16,0),
Z = 4x+4y = 4(16) + 4(0) = 64
2. Maximize P = 3x + 2y
Subject to x + y ≤ 8
2x + y ≤ 13
x ≥ 0, y ≥ 0
Plot the constraints and the objective function Z, or P=3x+2y.
Push the objective function to the limit in the increase + direction permitted by the feasible region to find the maximum intersection.
Answer: Objective function is at a maximum at (5,3),
Z = 3x+2y = 3(5)+2(3) = 21
Answer:

Step-by-step explanation:


comparing with equation







From the z-table and at p67 or 0.67 (the decimal values in the table),
Z =0.44
See the attached photo (at the point where 0.6700 appears)
Given
Brian's house: (-7, 9)
Sue's house: (-7, -2)
Find
The number of units between Brian's house and Sue's house.
Solution
Both Brian and Sue live on the "street" x=-7, so the distance between their houses is the distance between -2 on that street and +9 on that street. We always consider distance to be positive, so it doesn't matter whether we start at Brian's house and go -11 units to Sue's house, or start at Sue's house and go +11 units to Brian's house. Either way, we travel 11 units.
_____
"Displacement" is another matter. That has a sign associated with it and there is always a reference direction that is positive. Movement in the opposite direction results in a negative displacement. "Distance" is always positive.