Ok. Lets pretend you see a habitat in the wood. You see the food chain of all the animals. mouse, fox, bear, human. Lets say a zoo decides to get rid of their foxes and dumps them in this forest. Then, instead of 20, you have 30 foxes. All of the mice are gone in a matter of weeks. So the Foxes start to slowly drop out. Then, theres not much for the bears to eat, so the bears start dying. Then, the humans can't hunt bears. It sets the whole chain of the forest off. Next, the humans will switch to dears, and all the dears will be killed off... etc... etc... Make sense? Got a question? Message me for more details and more questions!
From One Smartie to Another- BubbleSmartie11
To calculate the frequency of the heterozygote genotype (Pq) for this gene we must use the Hardy-Weinberg equation ( p2 + 2pq + q2 = 1 ). This equation relies on the Hardy-Weinberg principle, a model in population genetics that states that the frequency of the alleles in a population is never changing, only the combinations (the genotypes) are changing.
If there are only two alleles (variations) of this gene in a population, then their frequencies should add up to 1 (100%). From this, we can calculate the frequency of the q allele.
p +q=1
0,3 +q=1
q= 1-0,3
q= 0,7
Now hat we have the frequency of the q allele we can use the HW equation to calculate the frequency of the heterozygotes.


0,09 + 2pq +0.49= 1
2pq +0,58= 1
2pq= 1-0.58
2pq=0,42
The freqency of the heterozygotes in this population is 0.42
Answer:
C. Sugar-phosphate groups
Neurons produce an action potential at the same time or none at all