2 years ago

What is the equation of a line in point-slope form passing through (-4,6) and (2, 3)?

Mathematics

2 answers:

777dan777 [17]2 years ago

7 0

The answer is y - 3 = -1/2 (x - 2).

First, let's find the slope.

m = y₂ - y₁ / x₂ - x₁
m = 3 - 6 / 2 + 4
m = -3/6
m = -1/2

Then, the point slope form will be :

y - 3 = -1/2 (x - 2)

Luba_88 [7]2 years ago

4 0

Answer: y=-0,5x+4.

Step-by-step explanation:

$A(-4;6)\ \ \ \ B(2;3)\\Straight \ line\ equation\ is:\\\displaystyle\\\boxed {\frac{x-x_1}{x_2-x_1} =\frac{y-y_1}{y_2-y_1}} \\\frac{x-(-4)}{2-(-4)}=\frac{y-6}{3-6} \\ \frac{x+4}{2+4}=\frac{y-6}{-3} \\\frac{x+4}{6}=\frac{y-6}{-3} \\ Multiply\ the\ left\ and\ right\ sides\ of\ the\ equation \ by\ -3:\\\frac{-(x+4)}{2} =y-6\\-0,5x-2=y-6\\y=-0,5x+4.$