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andrey2020 [161]
2 years ago
12

What is the equation of a line in point-slope form passing through (-4,6) and (2, 3)?

Mathematics
2 answers:
777dan777 [17]2 years ago
7 0

The answer is y - 3 = -1/2 (x - 2).

First, let's find the slope.

  • m = y₂ - y₁ / x₂ - x₁
  • m = 3 - 6 / 2 + 4
  • m = -3/6
  • m = -1/2

Then, the point slope form will be :

  • y - 3 = -1/2 (x - 2)
Luba_88 [7]2 years ago
4 0

Answer: y=-0,5x+4.

Step-by-step explanation:

A(-4;6)\ \ \ \ B(2;3)\\Straight \ line\  equation\ is:\\\displaystyle\\\boxed {\frac{x-x_1}{x_2-x_1} =\frac{y-y_1}{y_2-y_1}} \\\frac{x-(-4)}{2-(-4)}=\frac{y-6}{3-6} \\ \frac{x+4}{2+4}=\frac{y-6}{-3}  \\\frac{x+4}{6}=\frac{y-6}{-3} \\ Multiply\  the\  left\  and\  right\  sides\  of\  the\  equation \ by\  -3:\\\frac{-(x+4)}{2} =y-6\\-0,5x-2=y-6\\y=-0,5x+4.

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