Since supportive measures are designed to preserve both the complainant’s and the respondent’s access to education, interim removal of the respondent may occur if respondent poses an immediate threat or if his/her behavior is said to be disruptive of the said class and interferes with other activities.
<h3>What are supportive measures?</h3>
Supportive measures are known to be any form of an individualized services that is said to be often done so that they can be able to save, restore or keep the equal access of people to education, protect student and employee safety, as well as others.
Note that it is one that act to hinder any form of sexual harassment and as such, Supportive measures are known to be offered even if a the said complainant is a person who do not wish to start or participate in a grievance process.
Therefore, Since supportive measures are designed to preserve both the complainant’s and the respondent’s access to education, interim removal of the respondent may occur if respondent poses an immediate threat or if his/her behavior is said to be disruptive of the said class and interferes with other activities.
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The surface area of the smaller solid is found to be 214 square meters.
<h3>What is Surface area?</h3>
The surface area is given as the sum of the area of all the faces of a three-dimensional object.
The same shape has equivalent ratio of the surface area to volume. It is given as:
![\rm \dfrac{\sqrt{area_1}}{\sqrt{area_2}}=\dfrac{\sqrt[3]{Volume_1} }{\sqrt[3]{Volume_2} }](https://tex.z-dn.net/?f=%5Crm%20%5Cdfrac%7B%5Csqrt%7Barea_1%7D%7D%7B%5Csqrt%7Barea_2%7D%7D%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7BVolume_1%7D%20%7D%7B%5Csqrt%5B3%5D%7BVolume_2%7D%20%7D)
On considering the power of 6 at both the sides of the equation:

Considering area 1 and volume 1 for the larger solid, and area 2 and volume 2 for the smaller solid, substituting the values give:

By solving the above equation, the area of the smaller solid is found as 214 square meters. Thus, option B is correct.
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The matchup statement associated with rods or cones are:
<h3>Rods:</h3>
- involved with night vision
- smooth plasma membrane surrounding the intramembranous discs
- uses rhodopsin
- used in scotopic vision
- absorption peak occurs at 500 nm
<h3>Cones:</h3>
- highly concentrated in and around the macula
- involved with color vision
- infolded plasma membrane surrounds each disc
- uses photopsin
- absorption peaks occur at 420, 531, and 558 nm
<h3>What are the roles of rods and cones in the eye?</h3>
The Rods are known to help in regards to vision at low light levels or scotopic vision.
The cones are known to help or function in regards to vision at the point of higher light levels or what we call photopic vision.
Hence the matchup above are correct.
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<span>-What equation can be used to solve this work problem?
t/30 + t/20 = 1
</span><span>-How many minutes will it take both hoses to fill the pool?
12 minutes</span>