Answer : A
We need to simplify the given expression
Lets factor numerator first
=(2x+1)(x-3)
=(x+5)(x+3)
Now we factor the denominator
=(x+5)(x-4)
=(2x+1)(x-4)
Now we simplify it
Now cancel out same factors. so we left with
Now multiply the factors
4 poundsx2times per day= 8 pounds
8 pounds x 4 horses=32 pounds
32 poundsx 3 days = 96 pounds
Answer:
The probably genotype of individual #4 if 'Aa' and individual #6 is 'aa'.
Step-by-step explanation:
In a non sex-linked, dominant trait where both parents carry and show the trait and produce children that both have and don't have the trait, they would each have a genotype of 'Aa' which would produce a likelihood of 75% of children that carry the dominant traint and 25% that don't. Since the child of #1 and #2, #5, does not exhibit the trait, nor does the significant other (#6), then they both must have the 'aa' genotype. However, since #4 displays the dominant trait received from the parents, it is more likely they would have the 'Aa' genotype as by the punnet square of 'Aa' x 'Aa', 50% of their children would have the 'Aa' phenotype.
Answer:
C
Step-by-step explanation:
6:4=8:12
6x3=8
4x3=12
We are given a table showing the population and the area of different cities, A, B, C and D. To calculate the population density, divide the population over the total area of the city. The following statements are true:
<span>--The population density of City B is greater than that of City C.
--City D has the lowest population density of the four cities.
</span><span>--The population density for City B can be found using the ratio 48,592 : 26.</span><span>
</span><span>
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