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NARA [144]
3 years ago
9

a maintence worker is replacing worn rope on 6 flagpoles.The worker needs 40 feet of rope for each flagpole.At the hardware stor

e,rope is sold by the yard.how many yards of rope does the worker need to buy for all flagpoles
Mathematics
1 answer:
aniked [119]3 years ago
7 0

Answer: 80

Step-by-step explanation:

Do 6 x 40=240 to find the amount of rope needed in ft

Do 240 divided by 3 to convert to yards

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Lemur [1.5K]

Answer:

24

Step-by-step explanation:

Just multiply

6×4=24 :)

3 0
3 years ago
(-1/2 + 5/2) + a =0 solve for a
just olya [345]

Answer:

a = -2

i hope this helps

3 0
3 years ago
Read 2 more answers
Donata bought 4 lemons and 4 plums at the local supermarket for a total of $ 21.60. Dan bought 11 lemons and 6 plums at the same
VashaNatasha [74]
  1. you must establish a equation system  with the information given , 4x numbers of limon , where x represent the cost of every lemon and 4y numbers of plums , where y represents the cost of plums
  2. now  the equation system is 1) 4x+ 4y = 21,60 and 2) 11x+ 6y = 40.29
  3. of the equation 1 you must obtain the value of x, 4x = 21.60+4y ⇒x=21.60/4+4y/4⇒x= 5.4+y
  4. now with the value of x , it is substitute in the equation 2)   11(5.4+y) + 6y = 40.29 , ⇒ 59.4 + 11y + 6y = 40.29 ⇒  17y = 40.29-59.4⇒ y = -19,11/7⇒ y = -2.73
  5. the value of y is substitute in the equation 1) x = 5.4 + ( -2,73)⇒ x= 2,67,  where ,the price of every lemon is $ 2,67
6 0
3 years ago
PLEASE HELP ME I BEG
Kay [80]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identity

• 1 + cot²x = csc²x

Consider the left side

csc^{4} x - cot^{4} x

Factorise as a difference of squares

= (csc²x - cot²x)(csc²x + cot²x)

= (1 + cot²x - cot²x)(csc²x + cot²x)

= csc²x + cot²x

= csc²x + csc²x - 1

= 2csc²x - 1 = right side ⇒ verified




8 0
3 years ago
After the booster club sold 40 hotdogs at a football game, it had 90$ in profit. After the next game, it had sold a total of 80
sergiy2304 [10]
Let's first establish what we already know for this problem.

x = total number of hotdogs sold
y = total profit from total sales of hotdogs

Let's also establish the other equations which we will require in order to solve this problem.

Equation No. 1 -
Profit for 40 hotdogs = $90 profit

Equation No. 2 -
Profit for 80 hotdogs = $210 profit

STEP-BY-STEP SOLUTION

From this, we can use the formula y = mx + b & substitute the values for x & y from one of the two previous equations into the formula in order to obtain the values of m & b for the final equation. Here is an example of the working out as displayed below:

Firstly, using the first or second equation, we make either m or b the subject. Here I have used the first equation and made m the subject:

Equation No. 1 -
y = mx + b
90 = m ( 40 ) + b
40m = 90 - b
m = ( 90 - b ) / 40

Now, make b the subject in the second equation as displayed below:

Equation No. 2 -
y = mx + b
210 = m ( 80 ) + b
210 = 80m + b
b = 210 - 80m

Then, substitute m from the first equation into the second equation.

Equation No. 2 -
b = 210 - 80m
b = 210 - 80 [ ( 90 - b ) / 40 ]
b = 210 - [ 80 ( 90 - b ) / 40 ]
b = 210 - 2 ( 90 - b )
b = 210 - 180 - 2b
b - 2b = 30
- b = 30
b = - 30

Now, substitute b from the second equation into the first equation.

Equation No. 1 -
m = ( 90 - b ) / 40
m = ( 90 - ( - 30 ) / 40
m = ( 90 + 30 ) / 40
m = 120 / 40
m = 3

Through this, we have established that:

m = 3
b = - 30

Therefore, the final equation to model the final profit, y, based on the number of hotdogs sold, x, is as follows:

y = mx + b
y = ( 3 )x + ( - 30 )

ANSWER:
y = 3x - 30
3 0
3 years ago
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