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vfiekz [6]
2 years ago
11

An investor puts $2,500 into a life insurance policy that pays 10% simple annual interest. If no additional investment is made i

nto the policy, what is the total amount the investor should expect at the end of 5 years?
A) 125

B) 3,750

C) 1,250

D) 2,625
Mathematics
1 answer:
Novosadov [1.4K]2 years ago
4 0

Answer:

$3750

Step-by-step explanation:

Amount = principal + interest

Simple interest = Principal *Rate * time/100

Simple interest = 2500*10*5/100

Simple interest  = 25*50

Simple interest = $1250

Amount = $2500+$1250

Amount after 5 years is $3750

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tangare [24]

<u>Answer:</u>

The correct answer option is B. 21.

<u>Step-by-step explanation:</u>

We are given a figure where the line KL is intersecting another line MN such that angle from K to N is equal to the angle opposing it which is the angle measuring (5x).

Measure of angle K - N = 90° + 15° = 105°

Since angle K - N = angle M - L, we can write it as:

105° = 5x

x = 105/5

x = 21

Therefore, the correct answer option is B. 21.

3 0
3 years ago
Read 2 more answers
Please answer correctly !!!!!!!! Will mark brainliest !!!!!!!!!!
fomenos

Answer:

-8/3

Step-by-step explanation:

find slope

(-1,5) ( 2,-3 )

(-3 -5)/( 2-(-1)) = -8/3

7 0
3 years ago
I need help with a math problem it says to subtract 2y - 3 from 5y-10​
Alexeev081 [22]
The answer is 3y-7.hope this helps

7 0
3 years ago
Braving blizzard conditions on the planet Hoth, Luke Skywalker sets out at top speed in his snowspeeder for a rebel base 4800 mi
____ [38]

Answer:

v_top = 2400 mi/hr

v_w = 400 mi/h

Step-by-step explanation:

Given:

- Total distance D = 4800 mi

- Headwind journey time taken t_up= 3 hr

- Tailwind journey time taken t_down = 2 hr

Find:

Find the top speed of Luke's snow speeder and the speed of the wind.

Solution:

- The speed of Luke v_l is in stationary frame is given by:

                           v_l = v_w + v_l/w

Where,

           v_w: Wind speed

           v_l/w: Luke speed relative to wind.

- The top speed is attained on his returned journey with tail wind. We will use distance time relationship to calculate as follows:

                         v_top = D / t_down

                         v_top = 4800 / 2

                        v_top = v_down = 2400 mi/hr

- Similarly his speed on his journey up with head wind was v_up:

                         v_up = D / t_up

                         v_up = 4800 / 3

                        v_up = 1600 mi/hr    

- Now use the frame relations to find the wind speed v_w:

                         v_down = v_w + v_l/w

                         v_up = -v_w + v_l/w    

- Solve equations simultaneously:

                         2400 =  v_w + v_l/w

                         1600 =  -v_w + v_l/w

                         4000 = 2*v_l/w

                         v_l/w = 2000 mi/h

                         v_w = 400 mi/h

7 0
3 years ago
4.1 cm the scale on the map is 1 cm=4.5 km. What is the actual distance
evablogger [386]

If you are taking the cm to km then it would be like this

4.5km*4.1cm= 18.45km

5 0
3 years ago
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