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aivan3 [116]
2 years ago
10

Determine the equation of the parabola graphed below. Note: be sure to consider the negative sign already present in the templat

e equation when entering your answer. A parabola is plotted, concave up, with vertex located at coordinates negative three and negative four.
Mathematics
1 answer:
Blizzard [7]2 years ago
6 0

The equation of the graphed parabola is y=a(x+3)^{2}-4.

Given that parabola is plotted, concave up , with vertex located at coordinates (-3,-4).

We are required to find the equation of the graphed parabola.

The equation of a quadratic function of vertex (h,k) is given by:

y=a(x-h)^{2}+k

In the above equation a is the leading coefficient.

We have been given point (-3,-4).

We have to just put the value of h=-3 and k=-4 and the required equation will be as under:

y=a(x+3)^{2}-4

Hence the equation of the parabola which is plotted, concave up, with vertex located at coordinates (-3,-4) is y=a(x+3)^{2}-4.

Learn more about parabola at brainly.com/question/64712

#SPJ4

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50 POINTS SOLVE !! ::
satela [25.4K]

Answer:

<h2>k = 31/9</h2><h2>b = 12</h2>

Step-by-step explanation:

<u>k - 4</u> = 3

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k/9  = 3(9) + 4

k = 31/9

k = 31/9

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3 years ago
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Sedaia [141]

Answer:

x=12

10x = 120

5x = 60

Step-by-step explanation:

paralellograms will become 360 degrees

so 2(5x) +2(10x)= 360

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10x + 20x = 360

= 30x

divide both sides by 30 and isolate

<u>30x </u> = <u>360</u>

30        30

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multiply 12 by 10x and 5x

10x = 120

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3 years ago
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