When you arrange the N points in sequence around the polygon (clockwise or counterclockwise), the area is half the magnitude of the sum of the determinants of the points taken pairwise. The N determinants will also include the one involving the last point and the first one.
For example, consider the vertices of a triangle: (1,1), (2,3), (3,-1). Its area can be computed as
(1/2)*|(1*3-1*2) +(2*-1-3*3) +(3*1-(-1)*1)|
= (1/2)*|1 -11 +4| = 3
PART A
Change the fractions into improper fractions
pablo - rosa = 4 4/9 - 3 5/12
pablo - rosa = 40/9 - 41/12
Equalize the denominator of the fractions
I equalize them to 36. If the denominator 9 is multiplied by 4, so is the numerator. If the denominator 12 is multiplied by 3, so is the numerator.
pablo - rosa = 40/9 - 41/12
pablo - rosa = (40 × 4)/(9 × 4) - (41 × 3)/(12 × 3)
pablo - rosa = 160/36 - 123/36
pablo - rosa = 37/36
Change it to mixed fraction
pablo - rosa = 37/36
pablo - rosa = 1 1/36
Pablo has 1 1/36 quarts more than Rosa
PART B
Calculate the iced tea Pablo gave to Rosa
Change into proper fraction/improper fraction
iced tea given = 15% × 4 4/9
iced tea given = 15/100 × 40/9
iced tea given = 600/900
iced tea given = 2/3
Calculate Pablo's iced tea after giving
Pablo's = 40/9 - 2/3
Pablo's = 40/9 - (2 × 3)/(3×3)
Pablo's = 40/9 - 6/9
Pablo's = 34/9
Pablo's = 3 7/9
Calculate Rosa's iced tea
Rosa's = 41/12 + 2/3
Rosa's = 41/12 + (2 × 4)/(3 × 4)
Rosa's = 41/12 + 8/12
Rosa's = 49/12
Rosa's = 4 1/12
Pablo has 3 7/9 quarts and Rosa has 4 1/12 quarts
Let us assume the first number to be = x
Let us assume the second number to be = y
Then
x^2 - y^2 = 5
x^2 = y^2 + 5
And
3x^2 - 2y^2 = 19
Multiplying the first equation by -2, we get
- 2x^2 + 2y^2 = - 10
Now subtracting the two equations, we get
x^2 = 9
x = 3
Putting the value of "x" in the first equation, we get
(3)^2 - y^2 = 5
9 - y^2 = 5
y^2 = 4
y = 2
I hope that the procedure is clear enough for you to understand and this is the answer that you were looking for.
Answer: 3
Step-by-step explanation:
6y (1)
2 (2)
9x (3)
