Represent these consecutive numbers (assuming that they are all integers):
x
x+1
x+2
x+3
x+4
x+5
and so on
x+8
x+9 is the tenth number. x+9 = 10, so x = 9.
Think of it this way: there are 10 consecutive numbers, and the last one is 10.
Working backwards, we get the sequence 10, 9, ... 3, 2, 1.
The sum of such an arith sequence is equal to the count of the numbers times the average of the first and last terms:
sum here = 10(1+10)/2 = 5(11) = 55 (answer)
The answer is 19 I subtracted the 2 biggest numbers
Answer:
He ran one mile in 20 minutes
Step-by-step explanation:
Answer:
should also = 35* if I'm not mistaken
Step-by-step explanation:
if this is wrong I'm very sorry. if no one else helps u with in the next 10 mins I suggest using socratic, it helps me
Y = -3x + 13
Steps and the graph are on paper
