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8090 [49]
2 years ago
10

A square pool is surrounded by a paved area that is 2 metres wide. If the area of the paving is 72m2, what is the length of the

pool?
Mathematics
1 answer:
likoan [24]2 years ago
5 0

The length of the square pool is 8. 49cm

<h3>How to determine the area</h3>

Note that the formula for finding the area of a square is given as;

Area = length^2

We have

Area = 72 m²

Substitute into the formula

I^2 = 72

Find the square root of both sides

I= √72

I = 8. 49cm

The length of the square pool given as I is 8. 49cm

Thus, the length of the square pool is 8. 49cm

Learn more about area of a square here:

brainly.com/question/486778

#SPJ1

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Angelo is making a rectangular floor for a clubhouse with an area of 84 square feet. The length if each side of the floor is a w
Alexxandr [17]

Answer:

L=1 ft and B=84 ft

L=2 ft and B=42 ft

L=4ft and B=21ft

L=6ft and B=14 ft

L=7ft and B=12ft

L=12 ft and B=7ft

L=14ft and B=6 ft

L=21 ft and B=4 ft

L=42 ft and B=2 ft

L=84 ft and B=1 ft

Step-by-step explanation:

We are given that

Area of rectangular floor=84 square feet

We have to find the possible length and width of for Angelo's clubhouse.

Area of rectangle=length\times breadth

Using the formula

Area of rectangular floor for clubhouse=84 square feet

Length(L)\times breadth(B)=84

Factor of 84 are

1,2,4,6,7,12,14,21,42,84

Therefore,  possible dimension of rectangular floor

1ft\times 84ft,2ft\times 42ft,4ft\times 21ft,6ft\times 14ft,7ft\times 12ft,12ft\times 7ft,14ft\times 6ft,21ft\times 4ft,42ft\times 2ft,84ft\times 1ft

L=1 ft and B=84 ft

L=2 ft and B=42 ft

L=4ft and B=21ft

L=6ft and B=14 ft

L=7ft and B=12ft

L=12 ft and B=7ft

L=14ft and B=6 ft

L=21 ft and B=4 ft

L=42 ft and B=2 ft

L=84 ft and B=1 ft

5 0
3 years ago
Consider the expression 2√3 cos(x)csc(x)+4cos(x)-3csc(x)-2 √ 3 This expression can be represented as the product of the factors.
Alla [95]

Answer with explanation:

The given expression is:

 2 \sqrt{3}\cos x * \csc x+4 \cos x-3 \csc x-2\sqrt{3}\\\\=2 \cos x*(\sqrt{3}*\csc x+2)-\sqrt{3}*(\sqrt{3}*\csc x+2)\\\\\rightarrow (2\cos x -\sqrt{3})*(\sqrt{3}*\csc x+2)\\\\\rightarrow (2\cos x -\sqrt{3})*(\sqrt{3}*\csc x+2)=0\\\\(2\cos x -\sqrt{3})=0 \wedge (\sqrt{3}*\csc x+2)=0

  \cos x=\frac{\sqrt{3}}{2} \wedge \csc x=\frac{-2}{\sqrt{3}}\\\\x=\frac{\pi}{6},2\pi-\frac{\pi}{6}\\\\x=\frac{\pi}{6},\frac{11\pi}{6} \wedge x=\pi+\frac{\pi}{3} ,2\pi-\frac{\pi}{3}\\\\x=\frac{4\pi}{3},\frac{5\pi}{3}\\\\x={\frac{\pi}{6},\frac{11\pi}{6},\frac{4\pi}{3},\frac{5\pi}{3}}

Option C

8 0
2 years ago
A football is thrown from the stadium. The height of this football can be represented by the polynomial -16t2 +32t + 20, where t
olasank [31]

Answer:

C

Step-by-step explanation:

related equation

-16t^2 + 32t + 20 = 0

-4t^2 + 8t + 5 = 0

Δ/4 = 16 + 20 = 36

t1 = (-4 + 6)/-4 = -1/2

t2 = (-4 - 6)/-4 = 5/2

-16(t+1/2)(t-5/2)

-16(2t+1/2)(2t-5/2)

-4(2t+1)(2t-5)

5 0
3 years ago
Help solve this I’m not sure if my answer was right. Pythagorean theorem.
Ganezh [65]

Answer:

C. since 8, 15, 17 are pythagorean triples

8 0
3 years ago
Uh help it has to e same answers for all liek yk?
Finger [1]

Answer:

x = 8/3

Step-by-step explanation:

6x + 4 = 3x + 12

3x + 4 = 12

3x = 8

x = 8/3

5 0
3 years ago
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